Answer:
With 1 gallon of blueberries, Sam can fill 4/3 of his container.
Step-by-step explanation:
By the given situation:
1/2 gallon of blueberries ⇒ The container is 2/3 full
Now, let us assume 1 gallon of blue berries ⇒ The container is m full.
Now, by the RATIO OF PROPORTIONALITY:
![\frac{\frac{1}{2} }{\frac{2}{3} } = \frac{1}{m} \\\implies {\frac{1}{2} } \times {\frac{3}{2} } = \frac{1}{m}\\or,\frac{1}{m} = \frac{3}{4} \\\implies m = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%3D%20%5Cfrac%7B1%7D%7Bm%7D%20%5C%5C%5Cimplies%20%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5Ctimes%20%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7Bm%7D%5C%5Cor%2C%5Cfrac%7B1%7D%7Bm%7D%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20%5C%5C%5Cimplies%20%20m%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D)
Hence, with 1 gallon of blueberries, Sam can fill 4/3 of his container.
Answer:
Right tailed test
Step-by-step explanation:
The null hypothesis is:
![H_o: \mu \le 30](https://tex.z-dn.net/?f=H_o%3A%20%5Cmu%20%5Cle%2030)
The alternative hypothesis is:
![H_a: \mu > 30](https://tex.z-dn.net/?f=H_a%3A%20%5Cmu%20%3E%2030)
This is a right-tailed test since the alternative hypothesis is greater than 30
Suppose the level of significance is 0.05 and we are given a p-value less than 0.05.
Then, we reject the null hypothesis.
Answer:
w = 49 ft and l = 84ft
Step-by-step explanation:
P = 266
The formula for perimeter = 2(l+w)
We know the length is 35 more than the width
l = w+35
Substituting in for Perimeter
266 =2(l+w)
Now replacing l with w+35
266 =2(w+35+w)
Combine like terms
266 = 2(2w+35)
Divide each side by 2
266/2 = 2/2 (2w+35)
133 = 2w+35
Subtract 35 from each side
133-35 = 2w+35-35
98 = 2w
Divide by 2
98/2 = 2w/2
49 =w
We still need to find l
l = w +35
l = 49+35
l = 84
Answer:
x = 11
Step-by-step explanation:
8/4 = (x+5)/(x-3)
cross-multiply:
8(x-3) = 4(x+5)
8x - 24 = 4x + 20
4x = 44
x = 11
Answer:
8y + 10
Step-by-step explanation:
3 + (7 + 8y) =
Apply the associative property:
= (3 + 7) + 8y
= 10 + 8y
Apply the commutative property:
= 8y + 10