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klasskru [66]
3 years ago
6

Simplify: (2x-3)(4x+1)

Mathematics
1 answer:
mixas84 [53]3 years ago
3 0

Answer:

8x^2-10x-3

Step-by-step explanation:

(2x-3)(4x+1)

2x(4x+1)-3(4x+1)

8x^2+2x-12x-3

8x^2-10x-3

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Find the common ratio r for the geometric sequence and use r to find the next three terms. Enter your answer to four decimal pla
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Answer: The next three terms =2.56, - 1.024 and 0.4096

Step-by-step explanation:

Common Ratio of a Geometric sequence, R is calculated as

=a2/a1 = -40/100=-0.4

or a3/a2=16/ -40 = -0.4

such that the next three terms are

5th term =  -6.4 x -0.4=2.56

6th term= 2.56 x -0.4 =-1.024

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3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

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3 years ago
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