Solve the system of equations. 4х – 3y = 12 3х + 6у = 42

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

Answer: B. (6,4)

Find x for the 2nd equation

3x + 6y = 42

3x = 42-6y

x= (42-6y) / 3

Place the value of x in the first equation and find for y then.

4x - 3y= 12

4{(42-6y)/3} - 3y = 12

So the answer for y is 4

Now, you know the value of y is 4.

4x - 3*4 = 12

4x - 12 = 12

x= 12+12 /4

x= 6

So x is 6 and y is 4. So the answer is B.

Shkiper50 [21]3 years ago

6 0

The answer would be B) 6, 4

mark me brianliest if i was correct!

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The areas for half circle and rectangle are:

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Now we calculate the areas.

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