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irinina [24]
3 years ago
7

Can someone simplify 8.4 for me

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

84/10 (Thats the fraction of 8.4)

<u>42 </u>   =   8.40000

5

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Five more than 3 times a number
ipn [44]

Answer:

3x+5

Step-by-step explanation:

Let number =X

So

Five more than 3 times a number

3x+5

5 0
3 years ago
Read 2 more answers
In triangleABC, angle B= 90 degrees, cos(C)=15/17 and AB = 16 what is the measure of Angle A, Angle C and angle AC
Sergeeva-Olga [200]

Answer:

m∠C=28°, m∠A=62°, AC=34.1 units

Step-by-step explanation:

Given In ΔABC, m∠B = 90°, , and AB = 16 units. we have to find m∠A, m∠C, and AC.

As,  cos(C)={15}/{17}

⇒ angle C=cos^{-1}(\frac{15}{17})=28.07^{\circ}\sim28^{\circ}

By angle sum property of triangle,

m∠A+m∠B+m∠C=180°

⇒ m∠A+90°+28°=180°

⇒ m∠A=62°

Now, we have to find the length of AC

sin 28^{\circ}=\frac{AB}{AC}

⇒ AC=\frac{16}{sin 28^{\circ}}=34.1units

The length of AC is 34.1 units

3 0
4 years ago
Will ran 1 2/3 laps of a 1/4 mile track. How far, in miles, did Will run on that track?
MatroZZZ [7]

Answer:

\boxed{\frac{5}{12} \ miles}

Step-by-step explanation:

Will ran = 1 \frac{2}{3} \ of \ a \frac{1}{4} \ miles \ track

Will ran = \frac{5}{3} * \frac{1}{4}      [of means to multiply]

=> \frac{5*1}{3*4}

=> 5/12 miles

5 0
3 years ago
Bernie left home riding his bike at a rate of 15 mph Charlie left one hour later biking at a rate of 20 mph how long will it tak
3241004551 [841]

Answer:            

Bernie left home riding his bike at a rate of 15 mph.

Charlie left one hour later biking at a rate of 20 mph.

Bernie  distance = 15*t  (time is represented by t)

Charlie distance = 20*(t-1)  (he left after 1 hour)

15t = 20t - 20

-5t = -20        

t = 4

4*15 = 60

when t = 3 hours

3*20 = 60    

4 0
3 years ago
I need help on this.
mote1985 [20]

Let's go:


7 = x

38 + x = 180

x = 180 - 38

x = 142°


7 = 142°


I hope I helped you



5 0
4 years ago
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