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2 years ago

Solve for X. −68 < 8x − 4 < −36

2 answers:

7 0

You want to get x in the middle by itself.

Add 4 to all pieces.

-68 < 8x-4 <-36
+4 +4 +4

-64<8x <-32

Divide everything by 8

-64/8<8x/8<-32/8

-8< x <-4

Answer:: all the number between -8 and -4 but not counting them

Aloiza [94]2 years ago

4 0

Answer:

The required solution is $-8$ in interval notation (-8,-4).

Step-by-step explanation:

Consider the provided inequality.

$-68 < 8x - 4 < -36$

We need to solve the inequity for x.

Add 4 to the provided inequality.

$-68+4$

Divide both the sides by 8.

$-8$

Thus, the value of x is greater than -8 but less than -4.

The required solution is $-8$ in interval notation (-8,-4).

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Well in this problem we just have to work backwards doing everything opposite of what she did in order to get the final answer.
so she has 39 stamps at this moment. and since she bought nine more stamps lets subtract that value to see what she had before that.
1.) 39 - 9 = 30
now she has 30. but she said that before step one she sold half of them to buy that video game. so she divided her starting number by two. so again we are going to work backwards by multiplying the number by 2:)
2.) 30 x 2 = 60!!
3.) So she started out with 60 stamps
answer is 60:)
hope i helped

8 0

3 years ago

Identify the x-intercept and the y-intercept of the graph of 6x + 15y = −30.

Hunter-Best [27]

Answer:

D. x-intercept is -5 and the y-intercept is -2

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2 years ago

Choose the definition for the function

uysha [10]

Answer:

The answer is C.

Step-by-step explanation:

The first line's slope is 2x and it y-intercept is 4. The second line's slope is simple 1x or just x (they are both the same).

4 0

3 years ago

When p = 12, t = 2, and s= 6, r= 18. If r varies directly with p and inversely with the product of s and t, what is the

Luda [366]

Answer:

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9 months ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago