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3 years ago

-8b-32 what is the answer with work?

1 answer:

Crank3 years ago

7 0

Well the LCM (lowest common multiples) for 8 and 32 would be 4. So plug 4 into "b" -8×4-32. -8×4=32. -32-32. Since you can't subtract 32 and 32 you add! Which gives you -64.

Hope this helps (:

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago

Given: 8x-61=17, prove: 39/4

Degger [83]

Answer:

The solution is $x = \frac{39}{4}$

Step-by-step explanation:

We are given the following equation:

8x - 61 = 17

We want to find the solution, that is, the value of x. So

$8x - 61 = 17$

$8x = 78$

$x = \frac{78}{8}$

Simplifying by 2

$x = \frac{39}{4}$

The solution is $x = \frac{39}{4}$

8 0

3 years ago

If y = -5 when x = 2, find y when x = 8.

nasty-shy [4]

Answer:

Y= -20

Step-by-step explanation:

if y=-5 when x=2 find y when x=8

8 /2 = 4

=> x = 2 * 4 => x = 8 Answer

y = -5 * 4 =>

y= -20

4 0

2 years ago

Math question up here

Gemiola [76]

The answer is 11 because you do the smallest parenthesis. and work your way out.

7 0

3 years ago

Read 2 more answers

Please show me how to solve this equation step by step!<br> 1/25(20-t)=4/25t-3/5

rjkz [21]

Remark

Multiply both sides of the equation by 25. Then you have an equation that you have already done probably.

Step One

Multiply both sides of the equation by 25

1 * (20 - t) = 4t - (3/5) * 25 Every part of the equation must be multiplied by 25

(20 - t) = 4t - 75/5 3*25/5 = 75/5

20 - t = 4t - 15 Add t to both sides

20 - t + t =4t + t - 15 Combine like terms

20 = 5t - 15 Add 15 to both sides

20 + 15 = 5t - 15 + 15 Combine like terms

35 = 5t Divide by 5

35/5 = 5t/5 Switch sides

t = 7 Answer

5 0

3 years ago