<h3>
Answer: (4p^2+3)(p+2)</h3>
Work Shown:
I'm assuming you meant to write 4p^3+8p^2+3p+6
If so, then we would have these steps
4p^3+8p^2+3p+6
(4p^3+8p^2)+(3p+6)
4p^2(p+2)+3(p+2)
(4p^2+3)(p+2)
Answer:
The unit rate is accurately
(km/minute)
Step-by-step explanation:
(1,1/4) means that the vehicle traveled 1/4 km within 1 minute.
The unit rate for this problem is also known as the speed of the vehicle.
So to find the speed, you need to use distance over time.
---> Unit rate:
/ 1 =
(km/minute)
(2,1/2) means that the vehicle traveled 1/2 km within 2 minutes.
Same process:
---> Unit rate:
/ 2 =
Because of this, the unit rate is accurately
(km/minute)
Answer:
638638600
Hope that helps!
Step-by-step explanation:
Answer:
the answer for the equation 14
Answer:
Area of a trapezium = 1/2(a+b)×h
where a and b are parallel sides of the trapezium
h is the height
First question
We must first find the height of the trapezium using Pythagoras theorem
That's
h² = 8² -3²
h =√ 64 - 9
h = √ 55m
a = 7m
b = 10+3 = 13m
Area of the trapezoid = 1/2(7+13)×√55
= 1/2×20×√55
= 74.16
= 74m² to the nearest tenth
Second question
We use sine to find the height
sin30° = h/12
h = 12 sin 30°
h = 6 in
Let the other half of the parallel side be x
To find the other half of the parallel side we use Pythagoras theorem
That's
x² = 12²- 6²
x = √144-36
x = √108
x = 6√3 in
So for this trapezoid
a = 9 in
b = (9 + 6√3) in
h = 6 in
Area of the trapezoid = 1/2(9 + 9+6√3) × 6
= 1/2(18+6√3)×6
= 85.176 in²
= 85 in² to the nearest tenth
Hope this helps you