The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is

The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer:
g inverse = (1,a),(2,b),(c,3),(4,d)
Step-by-step explanation:
I think the third part of the question should be (c,3) not (2,3)
if it's (2,3) then the inverse becomes (3,2)
M = 20/-4 = -5
Sub in (-4,0): 20+b = 0 ->b = -20
So, y = -5x - 20
I took a19=-58 divide it by 19 both side i get a = -58÷19 (note; you can never have a neg. # on the top bring the neg. down to the bottom and divide) now its 58÷-19= -3.05 or -3 (1÷19) so a = -3(1/19) do the same to the other now. answer is a=-7 (17/21)