The muzzle velocity of an ancient cannon was about 420ft/s. What is the cannonball's speed in miles per hour?
1 answer:
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Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean =
Standard deviation =
Formula :
Now At x = 55
At x = 76
Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F =
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
<span>"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels m miles and is on a trip for x days then Rita will receive:
55x + 0.45m dollars.
Rita drove 300 miles, means that m=300. Thus </span>55x + 0.45m becomes <span>
</span>
(dollars.)
She was reimbursed $2,335 means that
.
Part A:.
Part B:
We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:
55x=2,335-135=2,200.
Dividing both sides by 55, we get: x=2,200/55=40.
Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip.
55x + 0.45m dollars.
Rita drove 300 miles, means that m=300. Thus </span>55x + 0.45m becomes <span>
</span>
She was reimbursed $2,335 means that
Part A:
Part B:
We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:
55x=2,335-135=2,200.
Dividing both sides by 55, we get: x=2,200/55=40.
Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip.