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mezya [45]
3 years ago
9

Solve the system of linear equations by elimination. Check your solution.

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

x = 3

y = -1

Step-by-step explanation:

(x-y) + (x+y) = 4 + 2

2x = 6

x = 3

sub x=3 into x+y=2

3+y=2

y=2-3

y=-1

Check by subbing x=3 and y=-1 into x-y=4

(3)-(-1) = 3+1 = 4

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(cos6x+6cos4x+15cos2x+10)/cos5x+5cos3x+10cosx
kakasveta [241]
Please see figure for answers

5 0
3 years ago
Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
5 0
2 years ago
Compute i^1+i^2+i^3....i^99+i^100
fgiga [73]

Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

Step-by-step explanation:

Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰

S =  i¹ +  i² +  i³ + . . . + i⁹⁹  +  i¹⁰⁰

S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀

then, S is the sum of 100 consecutive terms of a geometric sequence (an)

where the first term a1 = i¹ = i  and the common ratio = i

FORMULA:______________________

S=(term1)*\frac{1-(common.ratio)^{number.of.terms}}{1-(common.ratio)}

_______________________________

then

S=i*\frac{1-i^{100} }{1-i}

or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1  (we know that i⁴ = 1)

Hence

S = 0

7 0
3 years ago
What is the perimeter of the entire football field including the end zone
Dmitry [639]

Answer:

346 2/3 yards

Step-by-step explanation:

A football field is 100 yards long with each end zone being 10 years long, meaning the total length is 120 yards.

The width is 53 1/3 yards.

The perimeter is all the sides added, and a rectangle's, the shape of the field's, formula is p = 2l + 2w.

So if we plug it in and add it all up:

120 + 120 + 53 1/3 + 53 1/3

Perimeter = 346 2/3

4 0
3 years ago
Read 2 more answers
Some help would be appreciated
Elis [28]
She was driving an average of 51 mph.
3 0
3 years ago
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