Which statement describes volume?

Mathematics

1 answer:

devlian [24]3 years ago

7 0

Answer:

Volume is the quantity of three-dimensional space enclosed by a closed surface

Step-by-step explanation:

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T(x) = ax^5 + 2 where is a real number. If the points (-2, 66) and (2, -62) are on the graph of the function classify as one of

Sergeu [11.5K]

Answer:

a < -1

Step-by-step explanation:

Okay, so we are given this equation:

t(x) = ax^5 + 2

Lets plug in -2 as x and see what happens.. t(x) can be 66..

$a * (-2)^{5} + 2$ = 66

-32a + 2 = 66

-32a = 64

a = -2

A is less than -1,

a < -1

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2 years ago

Joel has $40 saved in his bank account. He plans to add $8.00 per week when he starts his lawn mowing business.

JulsSmile [24]

Answer:

The answer is Joel has to work for 10 weeks

Step-by-step explanation:

Trust me its correct

pls mark me as brainliest

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2 years ago

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two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : $v=\frac{distance}{time}$ . Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

$v\,*\,24\,min=d_A$

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

$v\,*\,32\,min=d_A+5\,miles$

Now we solve for $d_A$ in this last equation and make the substitution in the equation for car A:

$v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}$