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Leno4ka [110]
3 years ago
15

Solve this problem: X+7=12

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

x=5

Step-by-step explanation:

because 5+7=12

you can figure it out by doing 12-7=?

the answer is 5 and thats your x

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San<br> R<br> APOR is a right triangle. IF RO = 8, what is PO?<br> mios<br> 16
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PQ = 16

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Jim buys a calculator that is marked 30% off. If he paid $35, what was the original price?
liraira [26]

Answer:

x = 50

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5 0
3 years ago
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Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
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