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Troyanec [42]
2 years ago
12

Ameer uses \dfrac14 4 1 ​ start fraction, 1, divided by, 4, end fraction of a bottle of shampoo to give each of his dogs a bath.

He has 555 dogs all together.
Mathematics
1 answer:
svet-max [94.6K]2 years ago
7 0

Answer:

138 3/8

Step-by-step explanation:

total shampoo used for 555 dogs = 1/4 x 555 = 138 3/8 bottles

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What is the equation of a circle with center (1, -4) and radius 2?
kvv77 [185]

Answer:

(x-1)^2 + (y+4)^2 = 4

Step-by-step explanation:

The equation for a circle is given by

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-1)^2 + (y- -4)^2 = 2^2

(x-1)^2 + (y+4)^2 = 4

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2 years ago
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Paraphin [41]

Answer:

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Step-by-step explanation:

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2 years ago
Explain how to write the equation of a line if you know its y-intercept and the equation of a line to which it is parallel?
suter [353]
If you use the equation y = mx+b then you already know what the b term is because you have the y intercept. For the m (slope) you take the slope of the other line and use that because since there parallel they are going to run at the same angle (slope). Hope this helped. If you have any questions just ask.

6 0
2 years ago
Simplify the expression (x - 2y) + (3x + 4y)
CaHeK987 [17]

Simplifying the expression (x - 2y) + (3x + 4y).

Work:

(x - 2y) + (3x + 4y)

Combine like terms.

x + 3x = 4x

-2y + 4y = 2y

Reform the expression.

4x + 2y

Simplified Expression: 4x + 2y.

8 0
3 years ago
Find the A.P whose second term is 12 and 7th term exceeds the 4th by 15
Art [367]

The 2nd term exists 12 and 7th term exceeds the 4th by 15 exists AP : 7,12,17,....

<h3>How to estimate the arithmetic progression?</h3>

Given : The second term exists 12th and the 7th term exceeds the 4th term by 15

The formula of the nth term :

$a_{n}=a+(n-1) d

Where d exists a common difference

n be the number of terms

a be the first term

Substitute the value of n = 2

$a_{2}=a+(2-1) d=a+d

Let, the second term exists 12

So, a + d = 12 ..........(1)

Substitute the value of n = 7

$a_{7}=a+(7-1) d=a+6 d

Substitute n = 4

$a_{4}=a+(4-1) d=a+3 d

We are given that the 7th term exceeds the 4th term by 15

So, a+6d-a-3d = 15

3d = 15

d = 5

Substitute the value of d in (1)

So, a+5 = 12

a = 12-5

a = 7

AP : a,a+d,a+2d,.... = 5, 7+5, 7+2(5),....=7,12,17,....

Therefore, AP : 7,12,17,....

To learn more about arithmetic progression refer to:

brainly.com/question/24191546

#SPJ9

4 0
1 year ago
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