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a_sh-v [17]
3 years ago
8

Help please! Thanks in advance. :)

Mathematics
2 answers:
WARRIOR [948]3 years ago
7 0
The planes intersect in a line.  Lines are infinite in two directions.  If the planes are parallel they have no points in common.  It they intersect at a point they have only that point in common.  If they have no common point they have nothing in common.
amm18123 years ago
4 0
 i think the answer to your question is B. The planes have no common point.
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TRUE OF FALSE
Keith_Richards [23]

Answer:

false it does not change the shape but it does change the size

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
1 year ago
Twenty-five randomly selected students were asked the number of movies they watched the previous week. The results are as follow
guajiro [1.7K]

Answer:

a) x = 1.52

b) s = 1.16

Step-by-step explanation:

We have that:

5 students watched 0 movies.

9 students watched 1 movie.

5 students watched 2 movies.

5 students watched 3 movies.

1 student watched 4 movies.

(a) Find the sample mean x.

Sum divided by the number of students. So

x = \frac{5*0 + 9*1 + 5*2 + 5*3 + 1*4}{5 + 9 + 5 + 5 + 1} = \frac{38}{25} = 1.52

(b) Find the approximate sample standard deviation, s.

Standard deviation of the sample.

Square root of the sum of the squares of the values subtracted from the mean, divided by the sample size subtracted by 1. So

s = \sqrt{\frac{5*(0-1.52)^2 + 9*(1-1.52)^2 + 5*(2-1.52)^2 + 5*(3-1.52)^2 + 1*(4-1.52)^2}{24}} = \sqrt{\frac{32.24}{24}} = 1.16

3 0
3 years ago
A Math professor scores all tests with a maximum of 100 points. A student must have an average of 90 on six tests to receive an
nignag [31]

Answer:

No, he cannot

Step-by-step explanation:

Lets say the student takes the maximum socre on his last test, so he gets 100. Now, his average on the six texts will be:

(75+85+90+95+94+100)/6 = 89.83

So, if taking 100 is not enough to get to the average of 90, this means he would need a score greater than 100, which is impossible as 100 is the maximum. So, the student CAN'T get an A

3 0
4 years ago
Is this right?<br>please helpppp​
erastova [34]
Si, estoy seguro de que tienes razón
6 0
3 years ago
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