All categories

1 year ago

Given two of the side lengths, check all possible lengths for the third side. 15 ft and 27 ft

1 answer:

6 0

The triangle inequality theorem states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side; then:

15 + 27 = 42; 27 − 15 = 12. Therefore, third side must be less than

42 ft ant greater than 12 ft; so, possible lenghts for third side is given by the inequality: 12 < x < 42.

You might be interested in

Functions f(x) and g(x) are defined below. Determine where f(x) = g(x) by graphing.

Reika [66]

Answer:

Option D. x = 4

Step-by-step explanation:

we have

$f(x)=\frac{1}{x-3}+1$

$g(x)=2\sqrt{x-3}$

we know that

The solution of the system

f(x)=g(x)

is the x-coordinate of the intersection point both graphs

using a graphing tool

The intersection point is (4,2)

see the attached figure

therefore

The solution is x=4

8 0

4 years ago

Help pleaseee Im trying to get an A in class

likoan [24]

Answer:

191

Step-by-step explanation:

Sorry it's sideways. I drew a box chart for this. First, fill in what you know: the number of white and black beads Ally has. Then, calculate how many black beads Betty has (Ally's number, 59, minus 35.) 59-35 = 24.

They tell you the total number of beads is 346. Add up Ally's total to get 131, then subtract that from 346. That's Betty's total beads, 215.

Last, subtract the 24 black beads Betty has from the 215 total to get 191.

3 0

3 years ago

What are the solutions of x^2 = -7x-8

Vilka [71]

$Solution, solve\:for\:x,\:x^2=-7x-8\quad :\quad x=\frac{-7+\sqrt{17}}{2},\:x=\frac{-7-\sqrt{17}}{2}$

$Steps:$

$x^2=-7x-8$

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides},\\x^2+8=-7x-8+8$

$\mathrm{Simplify},\\x^2+8=-7x$

$\mathrm{Add\:}7x\mathrm{\:to\:both\:sides},\\x^2+8+7x=-7x+7x$

$\mathrm{Simplify},\\x^2+7x+8=0$

$Solve\:with\:the\:quadratic\:formula,\\\mathrm{For\:}\quad a=1,\:b=7,\:c=8:\quad x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1},\\x=\frac{-7+\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7+\sqrt{17}}{2},\\x=\frac{-7-\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7-\sqrt{17}}{2}$