Answer:
D. 5 +6k/n
Step-by-step explanation:
The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...
3/n
Then the difference between the left end point of the interval and the value of x at the right end of the k-th rectangle will be ...
k·(3/n) = 3k/n
So, the value of x at that point is that difference added to the interval's left end:
2 + 3k/n
The value of the function for this value of x is ...
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
This is the all question?
The answer you have selected is correct. The answer to this question is 90.
The zeroes of the function will be equal to ( 7, -6 ).
<h3>
What is a quadratic equation?</h3>
It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.
Given function:-
As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.
( x- 7 ) = 0
x = 7
( x+ 6 ) = 0
x = -6
Therefore zeroes of the function will be equal to ( 7, -6 ).
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Answer:
1
Anything to the 0th power is 1.
