Answer:
x = 1/2 or 2
Step-by-step explanation:
You can factor this as ...
2x^2 -4x -x +2 = 0 . . . rewrite the middle term to enable factoring
2x(x -2) -1(x -2) = 0 . . . . factor by grouping
(2x -1)(x -2) = 0 . . . . factor out (x -2)
x = 1/2, 2 . . . . . . values of x that make the factors zero
Step-by-step explanation:
Hey there!
While factorising you remember to make it take common in most of the expression.
Here;
=mx+cx+my+cy
Take common 'x' in "mx+cx" and 'y' in my + cy.
= x(m+c) + y(m+c)
Now, "(m+c)" common again.
= (m+c) (x+y)
Therefore the factorized form of the expression in (m+c)(x+y).
<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>
there are many combinations for it, but we can settle for say
![\bf \begin{cases} f(x)=x+2\\[1em] g(x)=\cfrac{9}{x^2}\\[-0.5em] \hrulefill\\ (f\circ g)(x)\implies f(~~g(x)~~) \end{cases}\qquad \qquad f(~~g(x)~~)=[g(x)]+2 \\\\\\ f(~~g(x)~~)=\left[ \cfrac{9}{x^2} \right]+2\implies f(~~g(x)~~)=\cfrac{9}{x^2}+2](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20f%28x%29%3Dx%2B2%5C%5C%5B1em%5D%20g%28x%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%28f%5Ccirc%20g%29%28x%29%5Cimplies%20f%28~~g%28x%29~~%29%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%28~~g%28x%29~~%29%3D%5Bg%28x%29%5D%2B2%20%5C%5C%5C%5C%5C%5C%20f%28~~g%28x%29~~%29%3D%5Cleft%5B%20%5Ccfrac%7B9%7D%7Bx%5E2%7D%20%5Cright%5D%2B2%5Cimplies%20f%28~~g%28x%29~~%29%3D%5Ccfrac%7B9%7D%7Bx%5E2%7D%2B2)
D: We solve this in exactly the same way in which we solved the previous area problem. Side length is s, area is s^2. Here, side length is 5 in; area is 25 in^2.
the problem does say, however, not to include units in your answer. Thus, just write "25."
Answer:
-3.84
Step-by-step explanation: