Answer:
How do you find the distance between two complex numbers?
For two points in the complex plane, the distance between the points is the modulus of the difference of the two complex numbers. (s − a)+(t − b)i = (s − a)2 + (t − b)2. So, d = (s − a)2 + (t − b)2 is the difference between the two points in the complex plane.
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
The question is on number of subsets
Number of subset is given by 2^n
n=3 in our question, A,B,C
2^n = 2^3 =8
They are; { }, A, B, C, AB, AC, BC, ABC
In 7 weeks Joy will have $230 and Cullen will have $230
Answer:
c. 8 units
Step-by-step explanation:
You are to find the y-intercepts of the two functions given, then report the difference between them. The y-intercept is the y-value when x=0.
For f(x), we have ...
f(0) = 3·2^0 = 3·1 = 3
__
For the table, we can see that x=0 is halfway between x=-2 and x=2, so the y-intercept can be expected to be halfway between y=3 and y=-13. That value for y is ...
g(0) = (3 + (-13))/2 = -10/2 = -5
That is, the y-intercept of g(x) is -5.
__
The difference between f(0) and g(0) is ...
f(0) -g(0) = 3 -(-5) = 8 . . . . units
x³y²
For this case, the first thing you should know is the properties of the exponents.
Let's write the full fraction:
(1) / (x ^ 3 * y ^ 2)
We have that by power properties:
(1) / (x ^ 3 * y ^ 2) = x ^ -3 * y ^ -2
Therefore the equivalent numerator is:
x ^ -3 * y ^ -2
Answer:
x ^ -3 * y ^ -2
