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Anit [1.1K]
3 years ago
13

What's the next step to substitution for this equation -4+y=-4

Mathematics
1 answer:
Marina86 [1]3 years ago
6 0
Subtract the y then add the 4 to the other side so y=0
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If sydney answer 15 questions in the first section correctly what is the minimum number of questions she must have answered corr
Mandarinka [93]

Answer:

8 Is correct on EDGE 2020

Step-by-step explanation:

Just took the test and got it right

3 0
4 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Tasya [4]

Answer:

\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]

Step-by-step explanation:

Given function:

y =\ln(\frac{(6 - x)^{\frac{3}{2}}}{x^{\frac{2}{3}}})

we know

\ln(\frac{A}{B}) = ln(A) - ln(B)

thus,

y = \ln((6 - x)^{\frac{3}{2}}) - \ln(x^{\frac{2}{3}})

or

also,

ln(Aⁿ) = n × ln(A)

thus,

y = (\frac{3}{2})\times\ln(6 - x) - (\frac{2}{3})\times\ln(x)

therefore,

\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]

or

\frac{dy}{dx}=-(\frac{3}{2(6-x)}) - (\frac{2}{3x})

or

\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]

or

\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]

5 0
4 years ago
Franco is reading a book with 482 pages. he reads 30 pages each night. how many pages will he read in 7 nights?
Alexeev081 [22]
120 because 30 times 7 is 120
4 0
3 years ago
Read 2 more answers
A small bag of flavor weighed 13 ounces. A large bag was 5 percent heavier.How much does the large bag weigh?
Novay_Z [31]
13+5=18
The large bag would be 18 because you have to add 5 more ounces than 13
5 0
4 years ago
How do you make x the subject of the formula when your formula is y= abx? Please can you show me how you worked it out if you an
GrogVix [38]
If you want to solve for x you have to get x alone on one side of the equals sign. In order to do that you have to get rid of the stuff on the same side by doing the opposite operation so that it cancels. What you do on one side you do on. the other side to keep the equation true.

y= abx

a and b are being multiplied by x so divide by ab to cancel them out (ab/ab is 1).

y= abx/ab (ab cancels)

now divide the other side by ab to keep the equation true.

y/ab= x

7 0
3 years ago
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