How to find coordinates -2,4

Mathematics

2 answers:

Setler79 [48]3 years ago

4 0

Answer: start at the origin (the center where the two bold lines intersect) and go left two notches. that is where -2 is. then go up 4 notches. that is where -2,4 is.

allsm [11]3 years ago

3 0

Answer:

Travel left across the X-Axis (Horizontal) -------- until you reach negative two (-2)

Then Travel up on the Y-Axis (Vertical) Until you get to your Y coordinate four (4)

Step-by-step explanation:

Connect both of your points to create a line.

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A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles:

vredina [299]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

(Please show all work) 1. Find f(6) if f(x)= 1/2x + x - 4

dsp73

Answer:

$\large\boxed{1.\ f(6)=5\ or\ f(6)=20}\\\boxed{2.\ d=5}\\\boxed{3.\ vertex=(-3,\ -1)}$

Step-by-step explanation:

$1.\\\text{Put x = 6 to the equation of a function}\ f(x):\\\\\text{If}\ f(x)=\dfrac{1}{2}x+x-4\to f(6)=\dfrac{1}{2}(6)+6-4=3+6-4=5\\\\\text{If}\ f(x)=\dfrac{1}{2}x^2+x-4\to f(6)=\dfrac{1}{2}(6^2)+6-4=\dfrac{1}{2}(36)+2=18+2=20\\\\2.\\\text{The formula of a distance between two points:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{We have the points (2, -4) and (5, -8). Substitute:}\\\\d=\sqrt{(5-2)^2+(-8-(-4))^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$

$3.\\\text{The vertex formula of a parabola:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\\\\text{We have}\ y=(x+3)^2-1=(x-(-3))^2-1\\\\\text{Therefore the vertex is:}\ (-3,\ -1).$