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Grace [21]
4 years ago
6

What is the equation for the line that passes through the points (0,5) (5,8)

Mathematics
1 answer:
mr Goodwill [35]4 years ago
7 0
The equation of a line is slope-intercept form which is y=mx+b. (0,5) is the y intercept so we know that b=5. To find the slope plug in the two points into y2-y1/x2-x1. 8 and 5 are the y’s so 8-5=3 over 5-0=5 so the final slope is 3/5. That makes the equation of the line y=3/5-5. Hope this helped!
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When writing an expression or equation to represent a real-world situation, why is it important to be able to describe what each
swat32

Answer:

If you know what each part of the expression or equations represents, it means that you understand the equation. You can solve the problem and know what you are doing.

I hope this helps! I'm sorry if it doesn't.

7 0
3 years ago
Please hurry!!Which type of angle is ZABC?
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Answer:

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3 0
3 years ago
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Answer:

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3 years ago
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Which of the following us the graph of f(x)=-0.5| x+3| -2
Evgesh-ka [11]
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3 years ago
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What are the x- and y-intercepts of the line tangent to the circle (x – 2)2 + (y – 2)2 = 25 at the point (5, 6)?
Tomtit [17]

I'm assuming you have. The first thing we do is find the slope of the tangent line by finding the derivative of the equation at the point (5,6).

expanding the equation

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Finding the derivative

2x - 4 + 2y y' - 4y' = 0

y'( 2y - 4) = 4 - 2x

y' = (4 - 2x) / (2y - 4)

at the point (5,6) the slope = y' = (4 - 10) / (12 - 4) = -3/4

So the equation of tangent line is y - 6 = -3/4( x - 5)

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so the y intercept = =3/4(0) + 39/4 = 39/4 Answer

and x intercept = -39/4 / - 3/4 = 13 Answer

8 0
3 years ago
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