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2 years ago

Where does the function y=2x-7 cross the y axis

Mathematics

1 answer:

nevsk [136]2 years ago

6 0

Let x=0, then we will get 2 (0)-7=-7. So the answer will be (0,-7)

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Roman55 [17]

$(x^3+x^2+x+2) divide by (x^2-1)$

We use long division to divide

There is no x term in x^2 -1 so we put 0x

x + 1

----------------------------

x^2+0x-1 x^3+ x^2 + x+ 2

x^3+0x^2-x

-----------------------------(subtract the bottom from top)

x^2 +2x + 2

x^2 +0x - 1

--------------------------------(subtract the bottom from top)

2x + 3

-----------------------------------------

Quotient : x+1

Remainder : 2x+3

5 0

2 years ago

Find the scale factor and similarity statement for both problems. Please help.

otez555 [7]

#5)
14/4 = 3.5
24.5 / 7 = 3.5

The pair is similar and SF = 3.5

#6)
10/4 = 2.5
21/9 = 2.3333

The pair is not similar because the corresponding sides are not proportional.

4 0

3 years ago

10 points! Please help if able!

TEA [102]

The 30/60/90 right triangle is the biggest cliche in trig. We recall the sides come in ratio $1:\sqrt{3}:2$

$1:\sqrt{3}:2 = x:y:4\sqrt{2}$

First x:

$\dfrac x 1 = \dfrac{4 \sqrt{2}}{2}$

$x = 2 \sqrt 2$

Next y:

$\dfrac{y}{\sqrt{3}} =\dfrac{x}{1}$

$y= 2 \sqrt{2} \sqrt{3} = 2 \sqrt{6}$

Choice C

3 0

2 years ago

A random variableX= {0, 1, 2, 3, ...} has cumulative distribution function.a) Calculate the probability that 3 ≤X≤ 5.b) Find the

olchik [2.2K]

Answer:

a) P ( 3 ≤X≤ 5 ) = 0.02619

b) E(X) = 1

Step-by-step explanation:

Given:

- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:

$F(X) = P ( X =< x) = 1 - \frac{1}{(x+1)*(x+2)}$

Find:

a.Calculate the probability that 3 ≤X≤ 5

b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that

Solution:

- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

$F(X) = P ( 3=$

- The Expected Value can be determined by sum to infinity of CDF:

E(X) = Σ ( 1 - F(X) )

$E(X) = \frac{1}{(x+1)*(x+2)} = \frac{1}{(x+1)} - \frac{1}{(x+2)} \\\\= \frac{1}{(1)} - \frac{1}{(2)}\\\\= \frac{1}{(2)} - \frac{1}{(3)} \\\\= \frac{1}{(3)} - \frac{1}{(4)}\\\\= ............................................\\\\= \frac{1}{(n)} - \frac{1}{(n+1)}\\\\= \frac{1}{(n+1)} - \frac{1}{(n+ 2)}$