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3 years ago

Find a rational number halfway in between two numbers 4/7 and 1/8

Mathematics

2 answers:

user100 [1]3 years ago

8 0

I think it’s 5/14 not positive but pretty sure

Makovka662 [10]3 years ago

3 0

Answer:

you did good how old are you is smart

Step-by-step explanation:

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6.52 7.25 13.05 43.50

gtnhenbr [62]

Total hours worked: 6 + 4 + 8 = 18 hours.

To find her hourly rate, divide the total pay by total hours worked:

130.50 / 18 = $7.25

6 0

3 years ago

Help me pls lol I don’t understand

Leona [35]

J = (5,6)
K = (5,1)
L = (10,2)

7 0

2 years ago

Read 2 more answers

75 out of 300 oranges in a basket are bad. what percent age of the oranges are (a) bad (b)good

Likurg_2 [28]

Answer:

a) 25% are bad

b) 75% are good

Step-by-step explanation:

We know that there are 300 oranges total and that 75 are bad. That means that the rest are good (implied).

300 - 75 = 225 good oranges.

So to find the percentage we have to take the selected amount divided by the total amount.

Bad Apples: Good Apples:

75 / 300 = 0.25 225/300 = 0.75

However, that's a decimal or a number out of 1, we need a percent or a number out of 100. So we have to multiply both numbers by 100.

Bad Apples = 25%

Good Apples = 75%

7 0

2 years ago

Find the radius of convergence and the internval of convergence:

o-na [289]

You can use the root test here. The series will converge if

$L=\displaystyle\lim_{n\to\infty}\sqrt[n]{\frac{(4-x)^n}{4^n+9^n}}$

You have

$L=\displaystyle\lim_{n\to\infty}\sqrt[n]{\frac{(4-x)^n}{4^n+9^n}}=|4-x|\lim_{n\to\infty}\frac1{\sqrt[n]{4^n+9^n}}$

Notice that

$\dfrac1{\sqrt[n]{4^n+9^n}}=\dfrac1{\sqrt[n]{9^n}\sqrt[n]{1+\left(\frac49\right)^n}}=\dfrac1{9\sqrt[n]{1+\left(\frac49\right)^n}}$

so as $n\to\infty$ , you have $\left(\dfrac49\right)^n\to0$ , which means you end up with

$L=\dfrac{|4x-1|}9$

This is the interval of convergence. The radius of convergence can be determined by finding the half-length of the interval, or by solving the inequality in terms of $|x-c|$ so that $R$ is the ROC. You get

$|4x-1|$

5 0

4 years ago

Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Giv

Marianna [84]

Answer:

Correct options is (A).

Step-by-step explanation:

A (1 - α)% confidence interval can be constructed to determine whether there is any difference between the average GPA of seniors and the average GPA of sophomores.

The hypothesis can be defined as:

H₀: There is no difference between the average GPA of seniors and the average GPA of sophomores, i.e. μ₁ - μ₂ = 0.

Hₐ: There is a difference between the average GPA of seniors and the average GPA of sophomores, i.e. μ₁ - μ₂ ≠ 0.

The (1 - α)% confidence interval for the difference between two means is:

$CI=(\bar x_{1}-\bar x_{1})\pm z_{\alpha /2}\times SE$

Decision rule:

If the confidence interval contains the mull value, i.e. 0, then the null hypothesis will be failed to be rejected and vice-versa.

The 95% confidence interval for the difference between the true average GPAs (seniors - sophomores) is (0.53, 1.61).

The 95% confidence interval dos not contains 0. Thus, the null hypothesis will be rejected.

Conclusion:

There is a significant difference between the average GPA of seniors and the average GPA of sophomores.

The 95% confidence interval for the difference between the true average GPAs (0.53, 1.61), implies that there is a 95% confidence that the average GPA of seniors is greater than the average GPA of sophomores.

Thus, the correct options is (A).

4 0

3 years ago