What is the slope of y= 5+3x

Las edades de dos hermanos tienen una razón de 2 a 1. Cuando transcurran 4 años, la razón entre sus edades será de 8 a 6. ¿Cuánt

Nataly [62]

Answer:

The age of brothers are 4 years and 2 years respectively.

Step-by-step explanation:

We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.

Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.

So, according to the question;

The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;

$\frac{x}{y} =\frac{2}{1}$

$x=2y$ -------------- [equation 1]

The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;

$\frac{x+4}{y+4}=\frac{8}{6}$

$6({x+4})=8}(y+4)$

$6x+24=8y+32$

$6(2y)+24=8y+32$

$12y-8y=32-24$

$4y=8$

$y=\frac{8}{4}$ = 2 years

Putting the value of y in equation 1 we get;

x = 2y

x = $2 \times 2$ = 4 years

Hence, the age of brothers are 4 years and 2 years respectively.

3 0

2 years ago

-5.8c+4.2-3.1+1.4c−5.8c+4.2−3.1+1.4c

Snowcat [4.5K]

Answer:

-10.2c + 2.2

Step-by-step explanation:

To make things less complicated, write down everything separate from the other. Then group together the intercepts and the coefficients into separate groups. After that, add them up separately in a format to where it will look like basic addition.

Hope this helps. I also apologize for any errors.

5 0

3 years ago

Multiply and simplify: -3ab^3 • (-4a^4b^5)

grandymaker [24]

$-3ab^3 * (-4a^4b^5)=\\(-3)(-4)(a^{1+4})(b^{3+5})=\\12a^5b^{8}$

4 0

3 years ago

What is the interquartile range (IQR) of the data set? a. 6 b. 7 c. 12 d. 13

Effectus [21]

Answer:

Step-by-step explanation:

#456sghSDFG

4 0

3 years ago

Read 2 more answers

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so