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Kay [80]
3 years ago
15

When using a NUMBERED list, you do not have to number each item. HTML automatically numbers each item in the order the items are

listed."
True
False​
Computers and Technology
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

Answer:

hypertext markup language

Explanation:

i hope this helps, though im not sure weather your asking what HTML means, or a list of uses for HTML.

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"Write a program that calculates the balance of a savings account at the end of a period of time. It should ask the user for the
Akimi4 [234]

Answer:

#include <iostream>

#include <fstream>

using namespace std;

int main() {

// Definitions

       double annualInterest;          // The annual interest rate

       double balance;                 // The account balance

       int months;                     // Total number of months

       double totalDeposit  = 0.0;     // Total deposited value

       double totalWithdraw = 0.0;     // Total withdrawn value

       double earnedInterest= 0.0;     // The earned amount

       double deposited;               // Monthly deposited value

       double withdrawn;               // Monthly withdrawn value

// Get the initial required data.

       

       cout<<"Please enter the annual interest rate,\n";

       cout<<"   Interest rate: ";

       cin >>annualInterest;

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the starting balance,\n";

       do{

           cout<<"[the number could not be negative]\n";

           cout<<"Starting Balance: ";

           cin >>balance;

       }while(balance<0);

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the number of months,\n";

       do{

           cout<<"[the number could not be less than 0]\n";

           cout<<"Number of months: ";

           cin >>months;

       }while(months<0);

// Iterated Loop to get all the months data.

       for(int month=1; month <= months; month++){

// Get the deposited value during that month.

           cout<<"Enter the deposited value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Deposited value: ";

               cin >>deposited;

           }while(deposited<0);

           

           totalDeposit += deposited;

           balance += deposited;

// Get the withdrawn value during that month.

           cout<<"Enter the withdrawn value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Withdrawn value: ";

               cin >>withdrawn;

           }while(withdrawn<0);

           

           totalWithdraw += withdrawn;

           balance -= withdrawn;

// Negative balance close the program.

           if(balance < 0){

               cout<<"Sorry, the account has been closed due to\n";

               cout<<"the negative balance.\n";

                 break;

// Calculate value due to the interest rate.

           }

      else {

               earnedInterest += (annualInterest/12) * balance;

               //        monthly interest rate

               balance += (annualInterest/12) * balance;

           }

       }

  // Display the statistics,

      ofstream file;

      file.open ("Report written to Report.txt");

      file << "Report written to Report.txt\n";

       file.close();

       cout<<"The ending balance: "<<balance<<std::endl;

       cout<<"   Total deposited: "<< totalDeposit<<std::endl;

       cout<<" Total withdrawals: "<< totalWithdraw<<std::endl;

       cout<<"   Earned interest: "<< earnedInterest<<std::endl;

       cout<<"============================================\n";

 return 0;

   }

   

6 0
3 years ago
9.A major step before taking print of the document is (3 points)
olya-2409 [2.1K]

Answer:

Uhyuuuuufuddirueueurururururru

8 0
3 years ago
g Write a function called price_of_rocks. It has no parameters. In a while loop, get a rock type and a weight from the user. Kee
Scilla [17]

Answer:

<u>The pseudocode:</u>

FUNCTION price_of_rocks():

  SET total = 0

  while True:

      INPUT rock_type

      INPUT weight

      if rock_type is "Quartz crystals":

         SET total += weight * 23

      elif rock_type is "Garnets":

         SET total += weight * 160

      elif rock_type is "Meteorite":

         SET total += weight * 15.50

       

       INPUT choice

       if choice is "n":

           break

 

   RETURN total

END FUNCTION

<u>The code:</u>

def price_of_rocks():

   total = 0

   while True:

       rock_type = input("Enter rock type: ")

       weight = float(input("Enter weight: "))

       

       if rock_type == "Quartz crystals":

           total += weight * 23

       elif rock_type == "Garnets":

           total += weight * 160

       elif rock_type == "Meteorite":

           total += weight * 15.50

           

       choice = input("Continue? (y/n) ")

       if choice == "n":

           break

   

   return total

print(price_of_rocks())

Explanation:

Create a function named price_of_rocks that does not take any parameters

Initialize the total as 0

Create an indefinite while loop. Inside the loop:

Ask the user to enter the rock_type and weight

Check the rock_type. If it is "Quartz crystals", multiply weight by 23 and add it to the total (cumulative sum). If it is "Garnets", multiply weight by 160 and add it to the total (cumulative sum). If it is "Meteorite", multiply weight by 15.50 and add it to the total (cumulative sum).

Then, ask the user to continue or not. If s/he enters "n", stop the loop.

At the end of function return the total

In the main, call the price_of_rocks and print

4 0
3 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
4 years ago
Using the following table as your starting point for each algorithm SJN Given the following information: Job: A B C D E Arrival
victus00 [196]

Answer:

Please check the attachment,

The average turnaround time is 4.8 and average waiting time is 1.

Please note: Exit time is same as completion time.

Explanation:

Please check the attachment.

7 0
3 years ago
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