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MaRussiya [10]
3 years ago
6

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

Computers and Technology
1 answer:
postnew [5]3 years ago
8 0

Answer: 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

Explanation: x1

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"talk to your landlord, creditors or bank about your financial situation to see if they can offer any leniency or a payment plan". just ask for extra time

Explanation:

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Are all the computer users known as programmer ​
Evgesh-ka [11]

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Nope

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What is the worst case time complexity of insertion sort where position of the data to be inserted is calculated using binary se
laiz [17]

Answer:

O(n²)

Explanation:

The worse case time complexity of insertion sort using binary search for positioning of data would be O(n²).

This is due to the fact that there are quite a number of series of swapping operations that are needed to handle each insertion.

4 0
3 years ago
Write a program to read a list of exam scores given as integer percentages in the range 0-100. Display the total number of grade
Tju [1.3M]

Answer:

import java.util.Scanner;

public class Program

{

  public static void main(String [] Args)

  {

      int totalAGrades = 0, totalBGrades = 0, totalCGrades = 0, totalDGrades = 0, totalFGrades = 0, counter=0,maximum = 0, minimum = 9999, num, total = 0,smallest = 0,largest = 0;

       Scanner in = new Scanner(System.in);

       System.out.println("Enter exam percentage: ");

       System.out.println("Enter a negative examScore: ");

       int examScore = in.nextInt();

       while(examScore > 0)

       {

         counter++;

         if(examScore < 0){          

             break;}  

         else if(examScore > maximum){      

              maximum = examScore;}

         else if(examScore < minimum)   {  

              minimum = examScore;}

         

          total = total + examScore;  

     

          if(examScore <= 50 && examScore>0)

              smallest = examScore;

              if(examScore > 90 && examScore <=100)

              largest = examScore;

         

      if(examScore>=90 && examScore<=100)

          totalAGrades++;

      else if(examScore>=80 && examScore<=89)

          totalBGrades++;

      else if(examScore>=70 && examScore<=79)

          totalCGrades++;

      else if(examScore>=60 && examScore<=69)

          totalDGrades++;

      else if(examScore>=0 && examScore<=59)

          totalFGrades++;

      examScore = in.nextInt();

     

   }

      System.out.println("Total number of scores is = " + counter );

      System.out.println("Total Number of each Letter grade : " + counter);

      System.out.println("Percentage of total for each letter grade : ");

          System.out.println("Total number of A grades = "+ totalAGrades);

          System.out.println("Total number of B grades = "+ totalBGrades);

          System.out.println("Total number of C grades = "+ totalCGrades);

          System.out.println("Total number of D grades = "+ totalDGrades);

          System.out.println("Total number of F grades = "+ totalFGrades);

     

      System.out.println("Lowest exam Score is :"+smallest);

      System.out.println("Highest exam Score is :"+largest);

      System.out.println("Average exam Score = "+ (total / counter));

  }

}  

Explanation:

  • Get the exam information from user as input and run a while loop until examScore is greater than zero.
  • Use conditional statement to check the scores of students and increment the relevant grade accordingly.
  • Finally display all the information including grades and scores.
3 0
3 years ago
Help guys thank you =) ​
MrRissso [65]
1.LR
2.LR
3.HR
4.LR
5.HR
6 0
3 years ago
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