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Oksi-84 [34.3K]
3 years ago
14

Tell me everything that happened in the fortnight galactics event. WHO EVER HAS THE BEST EXPLANATION WILL GET BONUS POINTS AND W

ILL BE MARK BRAINLYNESS
Computers and Technology
1 answer:
ryzh [129]3 years ago
7 0

Answer:

people still play fortnight?!?!

Explanation:

psn: Smallboy_life

You might be interested in
Write an HLA Assembly language program that prompts for a specific int8 value named n and then displays a repeated digit pattern
yan [13]

Answer:

Output:

123456

123456

123456

123456

123456

123456

Explanation:

C Code:

#include <stdio.h>

int main() {

int n,i,j;

printf("Gimme a decimal value to use as n:");

scanf("%d",&n);

for(i=0;i<n;i++){

for(j=1;j<=n;j++){

printf("%d",j);

}

printf("\n");

}

return 0;

}

Equivalent assembly program:

.LC0:

.string "Gimme a decimal value to use as n:"

.LC1:

.string "%d"

main:

push rbp

mov rbp, rsp

sub rsp, 16

mov edi, OFFSET FLAT:.LC0

mov eax, 0

call printf

lea rax, [rbp-12]

mov rsi, rax

mov edi, OFFSET FLAT:.LC1

mov eax, 0

call scanf

mov DWORD PTR [rbp-4], 0

.L5:

mov eax, DWORD PTR [rbp-12]

cmp DWORD PTR [rbp-4], eax

jge .L2

mov DWORD PTR [rbp-8], 1

.L4:

mov eax, DWORD PTR [rbp-12]

cmp DWORD PTR [rbp-8], eax

jg .L3

mov eax, DWORD PTR [rbp-8]

mov esi, eax

mov edi, OFFSET FLAT:.LC1

mov eax, 0

call printf

add DWORD PTR [rbp-8], 1

jmp .L4

.L3:

mov edi, 10

call putchar

add DWORD PTR [rbp-4], 1

jmp .L5

.L2:

mov eax, 0

leave

ret

Input:

6

The program was first written with a c code, anf and subsequently translated to an assembly language.

3 0
3 years ago
3.1.14 Wormhole CodeHS <br><br> May I have it in a copy and paste, please?
Sauron [17]

Answer:

3.1.14 Wormhole CodeHS

Explanation:

3.1.14 Wormhole CodeHS

6 0
3 years ago
Your objective is to create a set of files to be used as ‘flags’ that will be stored on computers used in a ‘capture the flag’ c
Semenov [28]

The following are the steps involved in the Process validation to the industry standard,

1)     Design of the process

2)     Qualification of the process

3)     Verification of the process

Explanation:

Validation is the process of finding whether the process meets its expected outcome.

1)     Construct knowledge about the process to be performed and establish a final design.

2)     Evaluation of the designed process is being done at this stage to rectify the errors and changes can be done.

Test the process to check whether the expected goal of the process being designed is achieved or not.

5 0
4 years ago
Write a program that computes the tax and tip on a restaurant bill for a patron a $88.67 meal charge. The tax should be 6.75 per
Lina20 [59]

Answer:

C++ code is writtern below with explanation in comments

Explanation:

#include <iostream>

using namespace std;

int main()

{

//declare all the required fields in double format

   double mealCost =88.67;

   double taxPercenatage=6.75;

   double tipPercentage=20;

// displaying the original Meal Cost

   cout<< "Meal Cost: "<<mealCost<<endl;

// get the total tax percentage from meal cost

   double totalTax= taxPercenatage /100 * mealCost;

// display the tax amount

   cout<< "Tax Amount: "<<totalTax<<endl;

// getting tip amount from meal cost and tax amount.

   double totalTip = tipPercentage/100 * (mealCost+totalTax);

//displaying tip amount

   cout<< "Tip Amount: "<<totalTip<<endl;

// now adding all three values and get total amount that customer

// has to pay

   double totalAmount = mealCost+totalTax+totalTip;

//Displaying total amount

   cout<< "Total Bill: "<<totalAmount<<endl;

   return 0;

}

Output

Meal Cost: 88.67

Tax Amount: 5.98523

Tip Amount: 18.931

Total Bill: 113.586

5 0
3 years ago
From the binary search algorithm, it follows that every iteration of the while loop cuts the size of the search list by half.
Colt1911 [192]

Answer:

True: In binary search algorithm, we follow the below steps sequentially:

Input: A sorted array  B[1,2,...n] of n items and one item x to be searched.

Output: The index of x in B if exists in B, 0 otherwise.

  1. low=1
  2. high=n
  3. while( low < high )
  4.  {      mid=low + (high-low)/2
  5.         if( B[mid]==x)
  6.          {
  7.             return(mid)  //returns mid as the index of x
  8.           }
  9.          else
  10.          {
  11.              if( B[mid] < x)      //takes only right half of the array
  12.               {
  13.                 low=mid+1
  14.               }
  15.              else               // takes only the left half of the array
  16.               {
  17.                high=mid-1
  18.               }
  19.           }
  20.  }
  21. return( 0 )

Explanation:

For each iteration the line number 11 or line number 15 will be executed.

Both lines, cut the array size to half of it and takes as the input for next iteration.

6 0
4 years ago
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