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Yuliya22 [10]
2 years ago
14

Line segment TS is tangent to circle O at point N.  If the measure of QNT  is 74°, what is the measure of QPN?

Mathematics
2 answers:
Ket [755]2 years ago
8 0
148         I just took the test.
Vinil7 [7]2 years ago
8 0

Answer:148

Step-by-step explanation:

I just took the test and I did the math and got it correct

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Sammi bought 2dozen valentines. How many valentines did sammi have left after giving 7/8 of them to her classmates
Ierofanga [76]
Dozen = 12

2 dozen

2x12=24

7/8 of 24

24 / 8 = 3 
3 x 7 = 21
24- 21= 3

3 roses are left over

8 0
3 years ago
The dishes have been sorted into cups and plates. The number of plates is four less than two times the number of cups. The dishe
Nady [450]

Answer:

The number of cups = 8 ....

Step-by-step explanation:

Let x be the number of cups

Let y be the number of plates

According to the given statement:

y=2x-4   This is equation 1

Now,

60% = 0.60

y=0.60(x+y)    This is equation 2

Now substitute equation 1 in equation 2.

y=0.60(x+y)

2x-4=0.60(x+2x-4)

2x-4=0.6x+1.2x-2.4

Solve the like terms:

2x-4=1.8x-2.4

2x-1.8x=4-2.4

0.2x=1.6

x=1.6/0.2

x= 8 cups

Therefore the number of cups = 8 ....

7 0
3 years ago
Will give <br> BRAINLY AND FIVE STARS and A THANKS
11Alexandr11 [23.1K]

Answer:

k = 12h

Step-by-step explanation:

Since each of the inputs of h can be mutiplied by 12 to get the output k, the equation is k = 12h
Hope this helps :)

3 0
2 years ago
HELP ASAP FOR BRAINLIEST!!
Diano4ka-milaya [45]

Answer:

Not equivalent

Step-by-step explanation:

The three would also be distributed to z making the correct equivalent expression 15+3z

8 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
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