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Alja [10]
3 years ago
12

Jozef works in a factory and is paid £352 a week. He works 40 hours a week. What is his hourly rate?

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

Step-by-step explanation:

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Pls help me I don't understand​
frutty [35]

Answer:

d. \:  \:  \: 25 {x}^{6}

Step-by-step explanation:

Given,

Side of the square

= 5 {x}^{3}

Therefore, area of the square = side × side

=  {5x}^{3}  \times 5 {x}^{3}

= 5 \times 5 \times  {x}^{3 + 3}

= 25 {x}^{6}

8 0
2 years ago
Read 2 more answers
ΔABC is a right triangle. Prove: a2 + b2 = c2 Right triangle BCA with sides of length a, b, and c. Perpendicular CD forms right
777dan777 [17]

Answer: Pythagorean Theorem Pieces of Right Triangles is not a justification for the proof.

Explanation : Here, \triangle ABC is a right triangle with sides a, b and c. Perpendicular CD forms right triangles BDC and CDA.

CD measures h units, BD measures y units, DA measures x units.

Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b, segment AB = c,  segment CD = h,  segment DB = y, segment AD = x,

y + x = c

a/c=y/a( Similarity theorem in triangles ABC and DBC )

a^2 = cy------(1) (Cross Product Property)

Similarly, b^2 = cx (Similarity theorem in triangles ABC and ADC)---------(2)

a^2 + b^2 = cy + cx(after adding equation (1) and (2) )

a^2 + b^2 = c(y + x)( By additional property of equality)

a^2 + b^2 = c^2. ( because y + x=c)

Thus, it has been proved that except Pythagorean Theorem Pieces of Right Triangles we use all other properties.

8 0
3 years ago
Read 2 more answers
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
Ad libitum [116K]

Answer:

C) ½

Step-by-step explanation:

P(C and D) = 150/300

= ½

5 0
3 years ago
40 POINTS + BRAINLIEST!
kotegsom [21]
Asnwer:
15 Units
Hope this helps! :)
4 0
2 years ago
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There is 1500 ft of fencing available to make 6 identical pens. Find the maximum area for EACH pen (meaning maximum of one pen).
hjlf

Answer:

The maximum area is therefore is 93750 ft²

Step-by-step explanation:

The given parameter are;

The a]length of fencing available = 1500 ft.

The perimeter of the figure = 9·x + 4·y

Therefore, 9·x + 4·y = 1500 ft.

The area of the figure = 6 × (x × y) = 3·x × 2·y

From the equation for the perimeter, we have;

9·x + 4·y = 1500

y = 1500/4 - 9/4·x = 375 - 9/4·x

y = 375 - 9/4·x

Substituting the value of y in the equation for the area gives;

Area = 3·x × 2·y = 3·x × 2·(375 - 9/4·x) = 2250·x - 27/2·x²

Area = 2250·x - 27/2·x²

The maximum area is found by taking the derivative and equating to zero as follows;

d(2250·x - 27/2·x²)/dx = 0

2250 - 27·x = 0

x = 2250/27 = 250/3

x = 250/3

y = 375 - 9/4·x = 375 - 9/4×250/3 = 187.5

The maximum area is therefore, 3·x × 2·y = 3 × 250/3 × 2 × 187.5 = 93750 ft²

The maximum area is therefore = 93750 ft.²

4 0
3 years ago
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