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3 years ago

Sup can someone help me with dis

Mathematics

2 answers:

brilliants [131]3 years ago

6 0

Choose 3 answers and those would be 8,20,100

attashe74 [19]3 years ago

5 0

Answer:

8,100,20

Step-by-step explanation:

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Ludmilka [50]

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Step-by-step explanation:

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3 years ago

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8. Show work here for 5(3d+5e+3)

Darya [45]

Answer:

15d+25e+15

Step-by-step explanation:

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4 0

3 years ago

What is the value of y? O A. Cannot be determined O B. 60 O C. 36 O D. 120 HELP!

Angelina_Jolie [31]

Answer: 60

Step-by-step explanation:

The three interior (inside) angles in a triangle will always add up to 180°.

60 + 60 + y = 180

120 + y = 180

-120

y = 60

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8 0

3 years ago

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On a piece of paper, graph y=4x-2. then determine which answer matches the graph you drew?

Natalka [10]

Because this equation is in slope-intercept form, we can tell exactly how it will look by checking out 3 key points.

Leading coefficient: negative, or positive.

In this case, the leading coefficient is positive, which means that the slope will be going from bottom left to upper right.

Leading coefficient = slope

In this case, the slope is 4, or 4/1, so it will be at a steep incline.

Value of constant = y-intercept.

In this case, the y-intercept is -2, which will help us narrow down our choice.

<h3>After reviewing the three answer choices, the most likely selection will be A, as it seems to have a slope of 4, it is positive, and it has a y-intercept of -2.</h3>

3 0

3 years ago

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

Hence proved.

4 0

3 years ago