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Lyrx [107]
3 years ago
15

Question 8 of 10

Mathematics
2 answers:
iren2701 [21]3 years ago
8 0

Answer:

7x-1

Step-by-step explanation:

  • f(x)+g(x)
  • 5x-2+(2x+1)
  • 5x-2+2x+1
  • 7x-1

lawyer [7]3 years ago
5 0

(f +G) means to add the two equations together:

5x - 2 + 2x +1

5x + 2x = 7x

-2 +  = -1

Answer is C. 7x-1

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For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
Problem 15-7 (Algorithmic) Speedy Oil provides a single-server automobile oil change and lubrication service. Customers provide
rodikova [14]

Answer: There are 4 average cars in the system.

Step-by-step explanation:

Since we have given that

Arrival rate = λ = 4 cars per hour

Service rate = μ = 5 cars per hour

We need to find the average number of cars in the system.

So, Average number of cars would be

L_q=\dfrac{\lambda^2}{\mu(\mu-\lambda)}\\\\L_q=\dfrac{4^2}{5(5-4)}\\\\L_q=\dfrac{16}{5}\\\\L_q=3.2

So, it becomes,

L=L_q=\dfrac{\lambda}{\mu}\\\\L=3.2+\dfrac{4}{5}\\\\L=3.2+0.8\\\\L=4

Hence, there are 4 average cars in the system.

6 0
3 years ago
Please help!!!!! I give free brainiest!!!
shusha [124]

We can use Copy Dot Flip to solve.

~Copy

3/4 ÷ 3/8

~Dot

3/4 · 3/8

~Flip

3/4 · 8/3

~Multiply both numerators and denominators.

3*8/4*3

~Simplify

24/12

~Simplify

2

The quotient is 2

Best of Luck!

6 0
3 years ago
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zhannawk [14.2K]

Answer:

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8 0
3 years ago
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A rectangular piece of cardboard has two circles punched out of it.
kramer

Step-by-step explanation:

18×14 = 252

2×( 3.14×1×1) = 6.28

252 - 6.28 = 245.72

= 246 centimetres squared

5 0
3 years ago
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