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2 years ago

Which of the following best defines a variable interval schedule of reinforcement?

Mathematics

1 answer:

worty [1.4K]2 years ago

5 0

Answer:

sam is reinforced every 2-10 days for putting his toys away.

Step-by-step explanation:

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DaniilM [7]

Answer:

Create drills athletes want to win. While everyone wants to win, make sure everyone is having fun too.

Set measurable goals, benefit out responsibility and roles, give ownership, and stop and listen to each other when something is wrong.

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5 0

3 years ago

Az+3z=bz+5<br><br> Lol help me

maw [93]

Answer:

a= -3 + b + 5/z Thats solved by factoring

let me k ow if you need more

Step-by-step explanation:

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3 years ago

PLEASE HELP ILL MARK BRAINLIEST

vodomira [7]

Answer:

y=x-3

Step-by-step explanation:

3 0

3 years ago

3/10y - 2/5 i need to find the coefficient and i dont know how

Rudik [331]

$\frac{3}{10y} - \frac{2}{5} = \frac{3 - 4y}{10y}$

7 0

3 years ago

You are making cookies for a party. The ratio of Cookie Tray A to Cookie Tray B to Cookie Tray C is 2 : 3 : 4. If you need to ma

Elenna [48]

Given that the ratio of three trays is A : B : C = 2 : 3 : 4

Let us consider the common factor among the number of trays be "x".

If we need to make a total of 171 trays, then the equation of sum of trays would be :-

Type A + Type B + Type C = 171

2x + 3x + 4x = 171

9x = 171

x = $\frac{171}{9}$ = 19

So we have following number of trays :-

Number of type A trays = 2x = 38 trays.

Number of type B trays = 3x = 57 trays.

Number of type C trays = 4x = 76 trays.

Now if each tray contains 20 cookies, then we would have following arrangements :-

Cookies in type A trays = 38×20 = 760 cookies.

Cookies in type B trays = 57×20 = 1140 cookies.

Cookies in type C trays = 76×20 = 1520 cookies.

4 0

3 years ago