Answer:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D)
Step-by-step explanation:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}\\\\\\=\left[ \left(\displaystyle x^{-\tfrac 35} \right)^{\tfrac 13 \right]^{\tfrac 58}\\\\\\=\left( \displaystyle x^{-\tfrac 35}\right)^{\tfrac 5{24}}\\\\\\=x^{ \displaystyle -\tfrac{3}{24} \right}\\\\\\=x^{\displaystyle -\tfrac 18 }\\\\\\=\dfrac 1{x^{\tfrac 18}}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%5B%20%5Cleft%28%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%20%5Cright%29%5E%7B%5Ctfrac%2013%20%5Cright%5D%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%28%20%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%5Cright%29%5E%7B%5Ctfrac%205%7B24%7D%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%20%5Cdisplaystyle%20-%5Ctfrac%7B3%7D%7B24%7D%20%20%5Cright%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%5Cdisplaystyle%20-%5Ctfrac%2018%20%20%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%201%7Bx%5E%7B%5Ctfrac%2018%7D%7D)
Answer:
8+6-10+2+15-3-7-5+2-15-8+10 = 5
Step-by-step explanation:
Answer:
y = 3x + 7
Step-by-step explanation:
A stem and leaf plot (histogram) shows the mode as the longest list of "leaves." It is the easiest to use for finding mode.
A box-and-whisker plot tells you nothing about relative frequencies.
A scatter plot or line graph would require careful re-interpretation to determine the mode. If the amount of data is large and there are many data values with about the same high frequency, these charts may be unhelpful, too.
Hey there!
(8 * 7 - 3) * 7
= 8(7)(7) - 3(7) ⬅️ POSSIBLY BE AN EQUIVALENT EXPRESSION
= 56(7) - 3(7)
= 392 - 3(7)
= 392 - 21
= 371 ⬅️ OVERALL ANSWER/EQUATION ANSWER
Most likely your answer should be:
• 8(7)(7) - 3(7)
• 56(7) - 3(7)
• 392 - 3(7)
• 392 - 21
EITHER OF THESE SHOULD WORK ⬆️
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
