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Tanzania [10]
2 years ago
14

What is the realashionship between ceels and tissues

Mathematics
1 answer:
zaharov [31]2 years ago
6 0
The relationship ship between cells and tissues is that a group of SIMILAR cells form a tissue so tissues consist of cells




That’s the similarity


Thank :)
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On Tuesday Emily bought four posters,
hram777 [196]

Answer: 16 posters

Step-by-step explanation:

Monday - Had owned 16 posters

Tuesday - Bought 4 posters, adding up to 20

Wednesday - Half of the posters were destroyed, half of 20 is 10

Thursday - 10 posters remained.

8 0
2 years ago
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Please help asap will give brainliest!!!
Helga [31]
There is a 1/3 chance of the spinner hitting any letter then the next time it would be another 1/3 chance. You multiply these together and get 1/9 but this is not the answer because there is 1/9 of BOTH happening so you add 1/9 plus 1/9 and get 2/9. The answer is 2/9.
7 0
3 years ago
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*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
A total of 26 bills are in a cash box. Some of the bills are one-dollar bills, and the rest are five-dollar bills. The total amo
kobusy [5.1K]

Answer:

Number of 1 $ bill = 20

Number of 5 $ bill = 6

Explanation:

 Let p represent number of one dollar bolls and q represent number of five bills.

A total of 26 bills are in a cash box.

      p + q = 26    ------------------------- Equation 1

The total amount of cash in the box is $50

      p + 5q = 50    ------------------------- Equation 2

Equation 2 - Equation 1,

        p + 5q - p -q = 50 - 26

        4q = 24

          q = 6

Substituting in equation 1.

         p + 6 = 26

         p = 20

Number of 1 $ bill = 20

Number of 5 $ bill = 6

3 0
3 years ago
Which of the following is true of the constructions of an equilateral triangle, a square, and a regular hexagon when they are in
lidiya [134]
<span>a regular hexagon inscribed in a circle </span>
6 0
3 years ago
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