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3 years ago

When like atoms are joined by a covalent bond the bonding electrons are shared?

Chemistry

1 answer:

Nutka1998 [239]3 years ago

7 0

Yes they are shared. So the answer is true.

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Fertilizer from an agricultural area runs off into a river. The river carries the nutrients from this fertilizer and deposits th

makkiz [27]

Answer:

i think it is oxygen

Explanation:

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3 years ago

If you travel from the Earth to the moon, which of the following measurements would change?

allsm [11]

Assuming you are talking about the individual in space, Size and Weight changes in space due to the difference in gravity. Astronauts grow taller in space due to the micro-gravity they experience out of the earth's atmosphere.

It would not be:
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4 years ago

Read 2 more answers

How many mass of chlorine molecule are found in 5 x 10^22 molecules of chlorine gas?

kompoz [17]

Answer;
Mass in gram/molecular mass=no.of molecule of Cl2 gas/Avogadro’s number(NA) - - - - - - - - -(1)
Here,
Molecular mass of cl2=35.5*2=71
No.of cl2 molecule=5*10^22
Avogadro’s number(NA)=6.032*10^23
Now,substituting these all value in equation one,we get,
Mass in gram =(no.of molecule)/NA)*molecular mass
Or,Mass in gram =(5*10^22/6.023*10^23)*71
Or,Mass in gram = 5.89gm.Ans

8 0

4 years ago

Description of the outer core of the earth

notka56 [123]

It is made of liquidy molten iron that is very hot.

5 0

4 years ago

References Use the References to access important values if needed for this question A student ran the following reaction in the

ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

2SO₂ (g) + O₂ (g) ⇔ 2SO₃ (g)

t = o 8.19x10⁻² 8.19x10⁻²

t = eq -2x -x 2x

--------------------------------------------- --------------------------

neq: 8.19x10⁻² -2x 8.19x10⁻² -x 2x

Given:

Equilibrium concentration of O₂ = 5.98x10⁻² M = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

$K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}$

$K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}$

K = 19.27

4 0

3 years ago