Answer:
A) (-1’,1‘)
B) (-1’,-2’)
C) (3’,-2’)
D) (3’,2’)
Step-by-step explanation:
A) (-1’,1‘)
B) (-1’,-2’)
C) (3’,-2’)
D) (3’,2’)
x=0
because you must
determine the undefined range
write all numerators above the common denomonator
multiply the parenthesis
collect the alike terms
remove parenthesis
eliminate the opposites collect the like terms
set the numerator equal to 0
divide both sides by 6
check if thesolution is the defined range
if so then you would find your answer X=0
Answer:
A
Step-by-step explanation:
The scale factor of the Reba's drawing is 9/84, 3/28
Step-by-step explanation:
The scale factor is the ratio between the two corresponding sides of the figure. The point worth noting in computing the scale factor is that both sides must have similar units of dimension while using for comparison purpose.
Given the scale used by Reba is 9 inches to 7 feet
Since both the units are different, we have the option to either convert inches to feet or vice versa
We proceed with converting feet to inches
We know that 1 foot equals to 12 inches. Hence 7 feet would equal 84 inches.
Now scale factor= first dimension/ corresponding dimension
Scale factor= 9/84 which can be reduced to 3/28
Answer:
See answers below for explanations (answers are in bold)
Step-by-step explanation:
<u>Problem 1 (Top left):</u>
Assuming that the shape is an ellipse, we will use the formula A=πab where a and b are both half the major and minor axis respectively. Since a=9 and b=6, then we have A = π(9)(6) = 54π = 169.646 units^2 as our final answer
<u>Problem 2 (Top right):</u>
Again, we use the same equation as in Problem 1 but this time, a=12 and b=8, so we then have A = π(8)(12) = 96π = 301.593 units^2 as our final answer
<u>Problem 3 (Bottom left):</u>
We can make this irregular shape into a half-ellipse and a rectangle. We would find their separate areas and add them up. The area of the half-ellipse would be A=1/2πab. The value of "a" would be 13.8/2=6.9 since that's the length of the rectangle. The value of "b" would be 3.5, so that means the area of the half-ellipse would be A = 1/2(π)(6.9)(3.5) = 12.075π = 37.935 units^2. The width and length of the rectangle are 5.4 and 13.8 respectively, so this means the area of the rectangle is 5.4*13.8 = 74.52 units^2. Combining both areas, we get 37.935+74.52 = 112.455 units^2 as our final answer
<u>Problem 4 (Bottom right):</u>
This irregular shape is an ellipse, but a circle is missing from its center. Thus, we must find the area of the circle and ellipse and then subtract the circle's area from the ellipse's area. For the area of the ellipse, a=(15.5/2)=7.75, and b=(7/2)=3.5, making its area A = π(7.75)(3.5) = 27.125π = 85.216 units^2. The area of a circle is A=πr² where "r" is the radius. The radius would be 7/2=3.5, making the circle's area A = π(3.5²) = 12.25π = 38.485 units^2. This means that the shaded area is 85.216-38.435 = 46.781 units^2
