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Alja [10]
2 years ago
5

Factories 24a³ + 37a² – 5a​

Mathematics
1 answer:
Semenov [28]2 years ago
4 0

Answer:

a(8a-1)(3a+5)

Step-by-step explanation:

24a³ + 37a² – 5a =

a ( 24a²+ 37a -5) =

a( 24a² +40a -3a -5) =

a [8a(3a+5) -1(3a+5) ]=

a(8a-1)(3a+5)

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Help me please , I don’t understand this very well , I’m trying to practice :/
SOVA2 [1]

Answer:

answer is 16

Step-by-step explanation:

x+17+x+19+8=x+34

2x+44=x+34

x+44=34

x=-10

-10+17+-10+19= HI

=16

7 0
3 years ago
Im bought 2 packs of batteries from a store. The price of each pack was the same. After he bought the batteries, his account bal
ololo11 [35]

Answer:

b

Step-by-step explanation:

$-23.94 / 2 is -11.97

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3 years ago
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Which of the following is the greatest? 0.65 0.67 0.62 0.668?
STatiana [176]
0.668 is the greatest.
If you have trouble because they have different place values, you can just and a "0" and the end of the decimals and they will still have the same value. Just make sure to change it back before writing your final answer.
8 0
3 years ago
HELPPP!!!!
Anon25 [30]

Answer:

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Step-by-step explanation:

Simple explanation:

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3 years ago
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Find possible zeroes<br> f(x)=3x^6+4x^3-2x^2+4
larisa [96]

The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are \mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

<h3>How to determine the possible zeros?</h3>

The function is given as:

f(x) = 3x^6 + 4x^3 -2x^2 + 4

The leading coefficient of the function is:

p = 3

The constant term is

q = 4

Take the factors of the above terms

p = 1 and 3

q = 1, 2 and 4

The possible zeros are then calculated as:

\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}

So, we have:

\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}

Expand

\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}

Solve

\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are \mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

Read more about rational root theorem at:

brainly.com/question/9353378

#SPJ1

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