Answer:
The 1st Blank is: A pure substance, or simply a substance
The 2nd blank on the left is: Elements
The 3rd blank on the right is: Compounds
The 4th blank which is the second middle one is: A mixture
The 5th blank which is the bottom left one is: Heterogeneous mixture
The 6th blank which is the last one on the bottom right is: Homogeneous mixture
Look at the step-by-step explanation if you get confused at the bottom.
Step-by-step explanation:
The 1st Blank: I would just put a pure substance.
The 2nd blank on the left: They are three characteristics of elements but just put elements.
The 3rd blank on the right: They are three characteristics of compounds but just put compounds.
The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.
The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.
The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.
Answer:
<u><em>x>2</em></u>
Step-by-step explanation:
<u><em>x3+3x2=7x+6</em></u>
<u><em>x3+3x2−(7x+6)=7x+6−(7x+6)</em></u>
<u><em>x3+3x2−7x−6=0</em></u>
<u><em>(x−2)(x2+5x+3)=0</em></u>
<u><em>x−2=0 or x2+5x+3=0</em></u>
<u><em>x=2 or x=−0.6972243622680054 or x=−4.302775637731995</em></u>
<u><em>x<−4.302776</em></u>
<u><em>−4.302776<x<−0.697224</em></u>
<u><em>−0.697224<x<2</em></u>
<u><em>x>2(Works in original inequality)</em></u>
Answer:
Step-by-step explanation:
Answer:
a1 = 6 and an = an-1 - 5
a2 = a2-1 - 5 = a1 - 5 = 1
a3 = a3-1 - 5 = a2 - 5 = -4, etc
Step-by-step explanation:
Answer:
v=3i+8j
Step-by-step explanation:
The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).
To find the components of vector v, we subtract the terminal points from the initial point to obtain.
v=<1,2>-<-2,-6>
v=<1--2,2--6>
v=<1+2,2+6>
v=<3,8>
As a linear combination of the standard unit vectors.
v=3i+8j
