Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
I could say that they will give you different answers since they are the same numbers and are in the same order but are paired differently
Answer:
Answer:
They both have q+3/2p, so that means that 2PQ=CB and that means they are parallel to each other
Step-by-step explanation:
PQ=PA+QA
PQ=1/2(2q-p)+2/5*5p=q-1/2p+2p=q+3/2p
CB=2q+3p=2(q+3/2p)
Other explanation: It should be written like this PQ=q+3/2p and CB=2q+3p=2(q+3/2p) they are parallel bcs CB=2*PQ.
Well i think it is true,because when you Multiplying you will not have a one decimal place