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madreJ [45]
3 years ago
15

Hello hello hello hello hello hello hello hello hello hello help help help help help help help help help

Mathematics
2 answers:
kiruha [24]3 years ago
8 0
1 month = 17 536
6 months = 17 536 x 6
6 months = 105 216

----------------------------------
Ans: 105 216 miles
----------------------------------
Crank3 years ago
6 0
The quick answer is 6 * 17536 = 105216 miles.

I would say it really depends on which 6 month period you are talking about because there are 28,30, and 31 days in a month. Then there is the problem of leap year.
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PLEASE HELP I NEEED HELP ASAP
dolphi86 [110]

Answer:

B

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab} and

\sqrt{-1} = i

Given

\sqrt{-80}

= \sqrt{16(5)(-1)}

= \sqrt{16} × \sqrt{5} × \sqrt{-1}

= 4 × \sqrt{5} × i

= 4i\sqrt{5} → B

6 0
3 years ago
4(x-6)=x+30 what is the answer
goldfiish [28.3K]

Answer:

18 is your answer

Step-by-step explanation:

First, distribute 4 to all terms within the parenthesis.

4(x - 6) = 4x - 24

4x - 24 = x + 30

Next, isolate the x. Add 24 to both sides, and subtract x from both sides

4x (-x) - 24 (+24) = x (-x) + 30 (+24)

4x - x = 30 + 24

Simplify. Combine like terms

3x =  54

Isolate the x. Divide 3 from both sides

(3x)/3 = (54)/3

x = 54/3

x = 18

---------------------------------------------------------------------------------------------------------

<em>~Senpai</em>

4 0
3 years ago
Proper
vlabodo [156]

Answer:

  QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)

Step-by-step explanation:

The diagram is not shown, but we assume the points are in the sequence ...

  P, Q, R, S, T

Since QR = RS, R is apparently the midpoint of QS, So ...

23. QR = 6/2 = 3

24. RS = QR = 3

25. PQ = QR = 3

26. ST = PT -PQ -QS = 20 -3 -6 = 11

27. RP = PQ +QR = 3 +3 = 6

28. RT = RS +ST = 3 +11 = 14

29. SP = PQ +QS = 3 +6 = 9

30. QT = QS +ST = 6 +11 = 17

6 0
3 years ago
2852.1 rounded to the nearest tenth of a mile
katrin2010 [14]
2852.1 rounded to the nearest tenth of a mile is still 2852.1
5 0
3 years ago
Read 2 more answers
Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:
Klio2033 [76]

Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

4 0
3 years ago
Read 2 more answers
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