All categories

2 years ago

How to write 9,009,009 in word form

Mathematics

2 answers:

svetoff [14.1K]2 years ago

8 0

Nine-million-nine-thousand-and nine Hope this is useful/helpful for you !! ^_^ !!

DaniilM [7]2 years ago

7 0

Nine million nine thousand and nine

You might be interested in

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4

kramer

Given:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function $h(t)=-16t^2+55t+4$ represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

Time:

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

$30=-16t^2+55t+4$

$26=-16t^2+55t$

Adding both sides of the equation by 16t², we get;

$16t^2+26=55t$

Subtracting both sides of the equation by 55t, we have;

$16t^2-55t+26=0$

Let us solve the quadratic equation using the quadratic formula, we get;

$t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}$

$t=\frac{55 \pm \sqrt{3025-1664}}{32}$

$t=\frac{55 \pm \sqrt{1361}}{32}$

$t=\frac{55 \pm 36.89}{32}$

$t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}$

$t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}$

$t=2.9 \ or \ t=0.6$

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

5 0

3 years ago

13•[18 divided by (15-9)} Evaluate

emmainna [20.7K]

The answer is 39.

13•[18/(15-9)]
= 13•[18/6]
= 13•3
= 39

8 0

3 years ago

Solve the equation. Type your answer in the box as positive or negative whole number (Examples: 2 -4 6 -8)

xxTIMURxx [149]

Answer:

-6n-5=31

Step-by-step explanation:

-6n=36

n=36/-6

n=(-6)

6 0

2 years ago

Read 2 more answers

Write the vector v in terms of i and j whose magnitude and direction angle θ are given.

Natali [406]

$\bf \begin{cases}
r=8\\
\theta =30^o
\end{cases}\qquad \qquad \qquad \qquad 
\begin{cases}
tan(\theta )=\frac{b}{a}\\
r^2=a^2+b^2
\end{cases}\\\\
-------------------------------\\\\
tan(30^o)=\cfrac{b}{a}\implies \cfrac{\quad\frac{1}{2} \quad }{\frac{\sqrt{3}}{2}}=\cfrac{b}{a}\implies \cfrac{1}{\sqrt{3}}=\cfrac{b}{a}\implies \boxed{\cfrac{a}{\sqrt{3}}=b}\\\\
-------------------------------$

$\bf 8^2=a^2+b^2\implies 64=a^2+b^2\implies 64=a^2+\left( \boxed{\cfrac{a}{\sqrt{3}}} \right)^2
\\\\\\
64=a^2+\cfrac{a^2}{3}\implies 64=\cfrac{4a^2}{3}\implies 16=\cfrac{a^2}{3}\implies 48=a^2
\\\\\\
\sqrt{48}=a\implies \boxed{4\sqrt{3}=a}\\\\
-------------------------------\\\\
\cfrac{a}{\sqrt{3}}=b\implies \cfrac{4\sqrt{3}}{\sqrt{3}}=b\implies \boxed{4=b}\\\\
-------------------------------\\\\
v~=~4\sqrt{3}i~+~4j$

3 0

3 years ago

Which equivalent expression will be generated by applying the Distributive Property and combining like terms in the expression 1

bazaltina [42]

$11+4(x+2y+4)$ , expanding the bracket gives
$11+4x+8y+16$ , collecting like terms give
$4x+8y+27$

8 0

3 years ago

Read 2 more answers