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3 years ago

Given (x, y ) = (5, 15). Find tan θ. a.3 b.1/3 c.5 d.1/5

Mathematics

2 answers:

Gre4nikov [31]3 years ago

7 0

Answer:

Step-by-step explanation:

You wouldn’t put y over x Which is 15/3 you would divide which gives you five. So your tan theta would be 5

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

it's definitely 3 on odyssey. tan theta= y/x =3.

Step-by-step explanation:

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Find the value of x that makes m||n

beks73 [17]

Answer:

x = 6

Step-by-step explanation:

In order for m to be parallel to n 16x - 6 would have to equal 90. We can demonstrate that using an equation.

16x - 6 = 90

Let's solve for x:

First add 6 to both sides to isolate the 16x:

16x - 6 + 6 = 90 + 6

16x = 96

Now divide both sides by 16 to isolate the x:

16x/16 = 96/16

x = 6

The value of x has to be 6 in order for m to be parallel to n.

7 0

3 years ago

Give an example that shows why you need to reverse the sign when dividing or multiplying an inequality by a negative number.

AnnZ [28]

Answer:

2 < 3 ⇒ -2 > -3

Step-by-step explanation:

∵ 2 < 3

If we divide each side by -1

∴ -2 < -3 but it's not true

∴ we must reverse the sign of inequality

∴ -2 > -3

similar:

∵ 25 > 20

If we divide each side by -5

∴ -5 > -4 it's not true

∴ we must reverse the sign of inequality

∴ -5 < -4

6 0

3 years ago

Solve the linear system below using the substitution method. <br> y = 5x – 22<br> 3x +2y=34

insens350 [35]

Answer:

Use photo math, it will explain all the steps

6 0

3 years ago

Read 2 more answers

Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation.

Alisiya [41]

Answer: b.

Step-by-step explanation:

Based on the information given, you can write the following expression:

$y=\frac{k}{x^2}$

Where k is the the constant of variation

If y=4/63 when x=3, then you can substitute these values into the expression and solve for k:

$\frac{4}{63}=\frac{k}{3^2}\\k=9*\frac{4}{63}\\k=\frac{4}{7}$

Substitute k into the expression. Then the equation is:

$y=\frac{4}{7x^{2}}$

Substitute x=5 into the equation. Then, y is:

$y=\frac{4}{7(5)^{2}}=\frac{4}{175}}$

8 0

4 years ago

Read 2 more answers

Element X decays radioactively with a half life of 12 minutes. If there are 160

Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

$X(t) = X(0)(1-r)^{t}$

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

$X(t) = X(0)(1-r)^{t}$

$X(t) = 160(1-r)^{t}$

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

$X(t) = 160(1-r)^{t}$

$80 = 160(1-r)^{12}$

$(1 - r)^{12} = 0.5$

$\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}$

$1 - r = 0.9438$

$X(t) = 160(1-r)^{t}$

$X(t) = 160(0.9438)^{t}$

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

$X(t) = 160(0.9438)^{t}$

$2 = 160(0.9438)^{t}$

$(0.9438)^{t} = \frac{2}{160}$

$\log{(0.9438)^{t}} = \log{\frac{2}{160}}$

$t\log{0.9438} = \log{\frac{2}{160}}$

$t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}$

$t = 75.8$

It would take 75.8 minutes for the element to decay to 2 grams.

6 0

3 years ago