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2 years ago

How many photocopies can you make for $2.00 at the rate of three copies for ten cents?

2 answers:

7 0

Convert $2 to cents, which is 200 cents.
10 cents =3 copies
200/10 =20
20x3 =60copies

or
10 cents =3copies,
100 cents =30copies.
100 x 2 =200cents.
2x30 copies =60 copies.

or in ratio form
10cents : 3copies
multiply 20 to get 200, you need to multiply on both sides,
= 200cents : 60copies

tigry1 [53]2 years ago

6 0

Im not 100% that thats correct but im pretty sure it is.

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What is 7.4% written as a decimal?

BlackZzzverrR [31]

$p\%=\frac{p}{100}\\\\7.4\%=\frac{7.4}{100}=\frac{7.4\cdot10}{100\cdot10}=\frac{74}{1000}=\boxed{0.074}$

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3 years ago

WILL GIVE BRAINLIEST!!!!!!!!!!!!!! Select the points that are solutions to the system of inequalities. Select all that apply

liq [111]

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2 years ago

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7nadin3 [17]

Answer true

Step-by-step explanation:

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2 years ago

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geniusboy [140]

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7 0

2 years ago

A triangular colourful scenery is made in a wall with sides 50 cm, 50 cm and 80 cm. A golden thread is to hang from the vertex s

gayaneshka [121]

Answer: The required length of the golden thread needed is 30 cm.

Step-by-step explanation: Given that a triangular colorful scenery is made in a wall with sides 50 cm, 50 cm and 80 cm. A golden thread is to hang from the vertex so as to just reach the side 80 cm.

We are to find the length of the golden thread required.

As shown in the attached figure below, ABC is the triangular scenery with sides

AB = AC = 50 cm and BC = 80 cm.

AD is drawn perpendicular to BC, so that AD is the length of the golden thread required to reach side BC with length 80 cm from the vertex A.

Now, since AD ⊥ BC and ΔABC is isosceles (AB = AC), so we must have

D is the midpoint of BC.

That is,

$BD=DC=\dfrac{1}{2}BC=\dfrac{1}{2}\times0=40.$

Now, from the right-angled triangle ABD, we have

$AB^2=BD^2+AD^2\\\\\Rightarrow AD^2=AB^2-BD^2\\\\\Rightarrow AD^2=50^2-40^2\\\\\Rightarrow AD^2=2500-1600\\\\\Rightarrow AD^2=900\\\\\Rightarrow AD=30.$

Thus, the required length of the golden thread needed is 30 cm.

7 0

2 years ago