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SVEN [57.7K]
3 years ago
8

Help me , this is my homework (Geometry) . I really need help

Mathematics
1 answer:
klemol [59]3 years ago
6 0

8. Similar parts


\dfrac{6}{18} = \dfrac{AQ}{12}


AQ = 12(6)/18=12/3=4


Choice a


9. The Law of Sines says a:b:c and \sin A : \sin B \sin C are the same ratio.


The sines will go in order for acute angles, we have to convert 120 to its supplement 60 and then the order is 29,31,"60" or opposite sides JK, KL, JL


choice b


10.


DEF and FEG are supplments, FEG=180-DEF=180-114=66


DEF and HEG are opposite angles, so congruent HEG=DEF=114


chioce a


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</span> For the domain we have:
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5 0
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Read 2 more answers
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ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
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2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
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x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
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x = 2y 
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y^2 = (2y)^2 - (22.5*sqrt(3))^2 
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y = 22.5
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10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
8 0
3 years ago
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