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3 years ago

C equals 2 pie r can you solve for r

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

$C=2 \pi r \ \ \to \ \ r= \cfrac{C}{2 \pi }$

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Solve the equation (linear equation)<br><br> <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B16%7D%7B9%7D%29%20%5E%7B2x%20%2B5%7D

nignag [31]

Answer: $x=-\frac{3}{5}$

Step-by-step explanation:

By the negative exponent rule, you have that:

$(\frac{1}{a})^n=a^{-n}$

By the exponents properties, you know that:

$(m^n)^l=m^{(nl)}$

You can rewrite 16 and 9 as following:

16=4²

9=3²

Therefore, you can rewrite the left side of the equation has following:

$(\frac{4^2}{3^2})^{(2x+5)}=(\frac{3}{4})^{(x-7)}\\\\(\frac{3^2}{4^2})^{-(2x+5)}=(\frac{3}{4})^{(x-7)}\\\\(\frac{3}{4})^{-2(2x+5)}=(\frac{3}{4})^{(x-7)}$

As the base are equal, then:

$-2(2x+5)=x-7$

Solve for x:

$-2(2x+5)=x-7\\-4x-10=x-7\\-4x-x=-7+10\\-5x=3\\x=-\frac{3}{5}$

6 0

3 years ago

I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

6 0

2 years ago

Read 2 more answers

1 2/5 as an improper fraction

Mrrafil [7]

Answer: 7/5. . . . .

6 0

2 years ago

The average cycling speed for an experienced cyclist is 18 miles per hour. What is the average cycling speed for an experienced

Anettt [7]

Answer:

1mile=5280

18miles=x

95040

1hour=60min

95040÷60=1584feet/minute

7 0

3 years ago

1) Helen is 8 years older than Jane. Twenty years ago Helen was three times as old as Jane. How old is each now and what is the

Mice21 [21]

Answer:

Part 1) Helen's age is 32 years old and Jane's age is 24 years old

Part 2) 13 twenty-dollar bills

Step-by-step explanation:

Part 1) Helen is 8 years older than Jane. Twenty years ago Helen was three times as old as Jane. How old is each now and what is the equation?

Let

x----> Helen's age

y---> Jane's age

we know that

x=y+8 ----> equation A

(x-20)=3(y-20) -----> equation B

substitute equation A in equation B and solve for y

(y+8-20)=3(y-20)

y-12=3y-60

3y-y=60-12

2y=48

y=24 years

Find the value of x

x=y+8

x=24+8=32 years

Part 2)

Let

x-----> the number of five-dollar bills

y----> the number of twenty-dollar bills

we know that

5x+20y=305 -----> equation A

y=x+4 ------> x=y-4 ------> equation B

substitute equation B in equation A and solve for y

5(y-4)+20y=305

5y-20+20y=305

25y=325

y=13 twenty-dollar bills

Find the value of x

x=y-4

x=13-4=9 five-dollar bills

5 0

2 years ago