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3 years ago

Line l bisects PQ at point M. Find value of X

Mathematics

1 answer:

Vanyuwa [196]3 years ago

7 0

Answer:

x = $\frac{18}{7}$

Step-by-step explanation:

Since l bisects PQ at M then M is the midpoint of PQ, hence

PM = MQ, that is

5x - 7 = 11 - 2x ( add 2x to both sides )

7x - 7 = 11 ( add 7 to both sides )

7x = 18 ( divide both sides by 7 )

x = $\frac{18}{7}$

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I NEED ASAP DUE IN 20 MINS

11111nata11111 [884]

Answer:

y = 45 / 2x + 50

Step-by-step explanation:

The best equation for the line of the best fit would be y = 45 / 2x + 50.

The slope would be 45 / 2 and the y-intercept would be ( 0 , 50 ).

I used the points, ( 0 , 50 ) and ( 4 , 140 ) to get the equation, slope, and the y-intercept.

I used those points because they were the most accurate ones that I know for now.

Also, remember the formula is, "y = mx + b."

4 0

2 years ago

Solve the following equations;- x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

$\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1$

Cross multiply ,

$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

$\sf\implies x^2+9^2-2.9.x = x +3 \\$

$\sf\implies x^2+81 - 18x = x -3$

Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

$\sf\implies ( x -13)(x-6)=0$

Equate both factors to 0 ,

$\sf\implies \boxed{\pink{\sf x = 13,6}}$

Hence the value of x is 13 or 6 .

7 0

3 years ago

Can i get help with 4,6, and 8 PLEASE HELP!!!!!!!!!! IM GONNA RUN OUTTA TIME!!!!

gogolik [260]

They are all even numbers

8 0

3 years ago

Please help thxxx I will mark brainlest !!!!

Harlamova29_29 [7]

Answer:

C) Y= x-1/2

Hope it helped !

5 0

3 years ago

If 8 identical blackboards are to be divided among 4 schools, how many divisions are possible? how many if each school must rece

DaniilM [7]

Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then

( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165

For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35

8 0

3 years ago