Answer:
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Answer:
mass of substance A=1.789
mass of substance B=2.185
now,
mass of substance B - mass of substance A
=2.185-1.789
=0.396
hence
mass of substance B is 0.396 gram greater than the mass of substance A
Answer:
4.4%
Step-by-step explanation:
solution:
principal (p) = $300
time(t) = 3 years
interest (I ) =$40
rate (r) = ?
we know that,
I = (PTR)/100*
OR, 40 = (300 *3 * R)/100
or, 40 = (900R)/100
or, 40 = 9R
or, 40/9 = R
or, R = 4.4%
Rate(r) =4.4%
The answer is 1690. First find
the amount of interest by a single investment by multiplying the investment
amount by the percent interest in decimal form. Then calculate the total by
adding up all the products of investment times interest. Matrices will allow to
multiply two things together and add the products up all at the same time. So
we need to find the investment matrix and interest matrix.
Investment matrix A (transposed) = (a1 a2 a3) = (13,000 12,000 4,000)
Interest Matrix B = (b1
b2 b3) = (0.05 0.06 0.08)
Amount of interest earned = a1b1 + a2b2 + a3b3
Amount of interest earned = (0.05) (13,000) + (0.06)
(12,000) + (0.08)(4,000)
Amount of interest earned = 1690
Area = (3x-5)(x-4) =
3x² - 12x - 5x + 20 =
3x² - 17x + 20
