The number of permutations of picking 4 pens from the box is 30.
There are six different unique colored pens in a box.
We have to select four pens from the different unique colored pens.
We have to find in how many different orders the four pens can be selected.
<h3>What is a permutation?</h3>
A permutation is the number of different arrangements of a set of items in a particular definite order.
The formula used for permutation of n items for r selection is:

Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1
We have,
Number of colored pens = 6
n = 6.
Number of pens to be selected = 4
r = 4
Applying the permutation formula.
We get,
= 
= 6! / 4!
=(6x5x4x3x2x1 ) / ( 4x3x2x1)
= 6x5
=30
Thus the number of permutations of picking 4 pens from a total of 6 unique colored pens in the box is 30.
Learn more about permutation here:
brainly.com/question/14767366
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This is the commutative property of addition. It basically says, x+y=y+x.
To answer your question, 103+21=21+103
Answer:
the first number is 6 the second number is 2 the third number is 2
Step-by-step explanation:
take 12 divided by 2 and u get 6 witch is the first number then u also get the second number witch is 2 then u take 6 divided by 3 and u get the third number witch is 2
2 ways to describe the proportion of 40% out of 50 points are:
20/50
or
2:5