Answer:
Percent Increase in measure of the side of a square = 30%
Step-by-step explanation:
Let the measure of the side of a square = s
Area of the square = (Side)²
= s²
If the area of the square is increased by 69%
Area of the new square = s² + 69% of s²
= s² + 0.69s²
= 1.69s²
Therefore, measure of the side of the new square = √(Area of the square)
= √(1.69s²)
= 1.3s
Measure of side of the old square = s
Therefore, increase in measure of the square = 1.3s - s
= 0.3s
Percent increase in the measure of the side of the square
= ![\frac{\text{Increase in measure}}{\text{Measure of the side of the original square}}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BIncrease%20in%20measure%7D%7D%7B%5Ctext%7BMeasure%20of%20the%20side%20of%20the%20original%20square%7D%7D%5Ctimes%20100)
= ![\frac{0.3s}{s}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B0.3s%7D%7Bs%7D%5Ctimes%20100)
= 30%
First find a common denominator so you can compare them easier. I chose 12. Multiply the numerator and denominator by the number that makes the denominator 12. 2/3 is multiplied by 4 and 2/4 is multiplied by 3. You are left with 8/12 and 6/12. 8/12 is bigger so it looks like
8/12>6/12
Hope this helps!
-4x is the slope and -12 is the y-intercept