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mezya [45]
4 years ago
8

Which expressions show the volume and the surface area of this cube-shaped packing box?

Mathematics
1 answer:
Jobisdone [24]4 years ago
5 0

Answer:

V=(13/8)3ft3; SA=6⋅(13/8)2ft2

Step-by-step explanation:

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In △MNK MN = NK, m∠N = 110º, MK = 5. Find MN.
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Answer:

MN = 3.03 ≈ 3

Step-by-step explanation:

Given: In ΔMNK MN = NK , m∠N = 110° and MK = 5.

To find: MN = ?

Sol: In ΔMNK,

∠M + ∠N + ∠K = 180°  (sum of angles of a triangle)

2∠M = 180° - 110°  ( ∠M =∠K since MN = MK)

∠M = 70°/2 = 35°

∴ ∠M = ∠K = 35°

Now, Using Sine Rule for finding sides,  

\frac{m}{sinM} = \frac{n}{sinN} = \frac{k}{SinK}

\frac{k}{sinK} = \frac{n}{sinN}

\frac{5}{sin 110^{\circ}} = \frac{k}{sin 35^{\circ}}

k = \frac{5 sin 35^{\circ}}{sin 110^{\circ}}

Now ∵ sin 35° = 0.57 and sin 110° = 0.94 approx.

By substituting these values in above expression,

k = \frac{5 \times 0.57}{0.94}

k = \frac{2.85}{0.94}

k = 3.03

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