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Kamila [148]
3 years ago
14

1. What is the theoretical probability that a coin toss results in 20 showing?

Mathematics
1 answer:
salantis [7]3 years ago
6 0
Ummm i dont even believe thats a reasonable question theres no 20 cent coins

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Somebody please help me with this question
denis23 [38]

Answer:

c is the correct answer

Step-by-step explanation:

3 0
2 years ago
What is the slope of the line that passes through the following points:<br> (4, -3), (-5, 10)
umka21 [38]

Answer:

-9/13

Step-by-step explanation:

The formula for slope is [ y2-y1/x2-x1 ].

10-(-3)/-5-4

13/-9

-9/13

Best of Luck!

5 0
3 years ago
In a triangle , the measure of the first angle is twice the measure of the second angle. The measure of the third angle is 100 m
madam [21]

Answer:

The three unknown angles X, Y , and Z are:

X = 40, Y = 20, and Z = 120

Step-by-step explanation:

Let's name X the measure of the first angle, Y the measure of the second one, and Z that of the third one.

Then we can create the following equations:

X = 2 Y

Z = 100 + Y

and

X + Y + Z = 180

So we use the first equation and the second one to substitute for the variable X and Z in the thrid equation:

2 Y + Y + (100 + Y) = 180

4 Y + 100 = 180

4 Y = 80

Y = 80/4 = 20

Then X = 40, Y = 20, and Z = 120

7 0
2 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
What is the interval notation for -3&lt;x&lt;4
kvv77 [185]
That would be (-3, 4)
4 0
2 years ago
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