All categories

3 years ago

What is common fraction?

Mathematics

2 answers:

Orlov [11]3 years ago

8 0

a fraction (such as ¹/₂ or ³/₄) in which the numerator and denominator are both integers and are separated by a horizontal or slanted line — compare decimal fraction.

Nady [450]3 years ago

3 0

A common fraction is a fraction expressed only by a numerator and denominator

You might be interested in

It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons a

Verizon [17]

Answer:

148 minutes

Step-by-step explanation:

It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons at 6{:}00\text{ p.M.}6:00 p.M.6, colon, 00, start text, space, p, point, m, point, end text How many minutes are there until Emma's gymnastics lessons?\

The time is 3:32 pm

Emma's gymnastics lesson is at 6:00 pm

6:00 pm - 3:32 pm = 2 hours 28 minutes

That is, we have 28 minutes before 4:00 pm

And 2 hours from 4:00 pm to 6:00 pm making a total of 2 hours 28 minutes

How many minutes are there until Emma's gymnastics lessons?

Convert 2 hours 28 minutes to minutes

1 hour = 60 minutes

2 hours = 60 minutes × 2 = 120 minutes

120 minutes + 28 minutes = 148 minutes

2 hours 28 minutes to minutes = 148 minutes

4 0

3 years ago

Can anyone help me with this? I know that angle B is 90°

sergey [27]

Answer:

angle c is 58 degrees and and angle a is 42 degrees

Step-by-step explanation:

3 0

2 years ago

20. Three cards are selected form a standard deck of cards and not

frozen [14]

We have a probability of $\frac{13}{52}=\frac{1}{4}$ for the first card to be a diamond. Having drawn this first card <em>without replacement,</em> there are now 12 diamonds remaining in a deck of 51 cards, so the probability that the second card is a diamond, given that the first card was a diamond, is $\frac{12}{51}=\frac{4}{17}.$ Similarly, for the third card, there are 11 diamonds in a deck of 50, so the probability of drawing a third diamond is $\frac{11}{50}.$ Now, since these events are dependent, we multiply these three probabilities to get our answer of $\frac{11}{850}.$

6 0

3 years ago

What is the Laplace Transform of 7t^3 using the definition (and not the shortcut method)

Leokris [45]

Answer:

Step-by-step explanation:

By definition of Laplace transform we have

L{f(t)} = $L{{f(t)}}=\int_{0}^{\infty }e^{-st}f(t)dt\\\\Given\\f(t)=7t^{3}\\\\\therefore L[7t^{3}]=\int_{0}^{\infty }e^{-st}7t^{3}dt\\\\$

Now to solve the integral on the right hand side we shall use Integration by parts Taking $7t^{3}$ as first function thus we have

$\int_{0}^{\infty }e^{-st}7t^{3}dt=7\int_{0}^{\infty }e^{-st}t^{3}dt\\\\= [t^3\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(3t^2)\int e^{-st}dt]dt\\\\=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\$

Again repeating the same procedure we get

$=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt= \frac{3}{s}[t^2\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t^2)\int e^{-st}dt]dt\\\\=\frac{3}{s}[0-\int_{0}^{\infty }\frac{2t^{1}}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{2}}[\int_{0}^{\infty }te^{-st}dt]\\\\$

Again repeating the same procedure we get

$\frac{3\times 2}{s^2}[\int_{0}^{\infty }te^{-st}dt]= \frac{3\times 2}{s^{2}}[t\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t)\int e^{-st}dt]dt\\\\=\frac{3\times 2}{s^2}[0-\int_{0}^{\infty }\frac{1}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{3}}[\int_{0}^{\infty }e^{-st}dt]\\\\$